All categories

1 year ago

20. Find the solution to the system of linear equations below:

Mathematics

1 answer:

Luden [163]1 year ago

3 0

Answer:

The last option

Step-by-step explanation:

When you plug in 1 for the x and 2 for y, the answer is -5 for the first equation and is 12 for the second equation. I hope that helps!

You might be interested in

Pls help i will give u brianliest

Fynjy0 [20]

Answer:

Slope = -3

y-intercept = (0,-4)

Equation: y = -3x-4

Step-by-step explanation:

We can take any two input-output pairs from the table to find the equation of given function.

Linear function is given by:

$y =mx+b$

Here m is the gradient of the functions which is defined as:

$m = \frac{rise}{run} = \frac{y_2-y_1}{x_2-x_1}$

The input-output pairs are:

(x1,y1) = (-1,-1)

(x2,y2) = (0,-4)

First of all,

$m = \frac{-4-(-1)}{0-(-1)}\\= \frac{-4+1}{1} = -3$

Putting the value of slope in the equation

$y = -3x+b$

Putting (-1,-1) in the equation

$-1 = -3(-1)+b\\-1 = 3+b\\b = -1-3\\b = -4$

The equation will be:

$y = -3x-4$

Hence,

Slope = -3

y-intercept = (0,-4)

Equation: y = -3x-4

7 0

3 years ago

Carol buys a house for £234 900

Aneli [31]

Answer:

23,490

Step-by-step explanation:

10% = 0.1

234900 x 0.1 = 23490

3 0

3 years ago

I need the domain range and function. With an explanation

erastovalidia [21]

<h3>Answers:</h3>

Problem 1

Domain = $-3 < x \le 3$ , interval notation (-3, 3]
Range = $-3 \le y < 3$ , interval notation [-3, 3)
Is it a function? Yes

Problem 2

Domain = $x \ge -2$ , interval notation $[-2, \infty)$
Range = All real numbers, interval notation $(-\infty, \infty)$
Is it a function? No

Problem 3

Domain = $-4 \le x < 3$ , interval notation [-4, 3)
Range = $-4 < y \le 3$ , interval notation (-4, 3]
Is it a function? Yes

Problem 4

Domain = All real numbers, interval notation $(-\infty, \infty)$
Range = $y \le 4$ , interval notation $(-\infty, 4]$
Is it a function? Yes

==================================================

Explanations:

The left most point is when x = -3, and we are not including this value due to the open hole. The other endpoint is included because it is a filled in circle. The domain is therefore $-3 < x \le 3$ which in interval notation is (-3, 3]. We have the curved parenthesis meaning "exclude endpoint" and the square bracket says "include endpoint". The range is a similar story but we're looking at the smallest and largest y values. Though be careful about which endpoint is open/closed. We have a function because it passes the vertical line test.
The smallest x value is x = -2. There is no largest x value because the arrows say to go on forever to the right. We can say the domain is $x \ge -2$ which in interval notation is $[-2, \infty)$ . The range is $(-\infty, \infty)$ to indicate "all real numbers". This graph fails the vertical line test, so it is not a function. The vertical line test is where we check to see if we can pass a vertical line through more than one point on the curve. In this case, such a thing is possible which is why it fails the test.
This is the same idea as problem 1, though note the endpoints are flipped in terms of which has an open circle and which doesn't. It is not possible to draw a single vertical line to have it pass through more than one point on the curve, so it passes the vertical line test and we have a function.
This is a function because it passes the vertical line test. The domain is the set of all real numbers due to the arrows in both directions. Any x value is a possible input. The range is $y \le 4$ which is the same as saying $(-\infty, 4]$ in interval notation. This is because y = 4 is the largest y value possible. There is no smallest y value due to the arrows.

7 0

3 years ago

Describe how to solve an exponential equation with unlike bases.

kari74 [83]

Answer:

Mark me as brainlist

Step-by-step explanation:

Use logarithms to solve exponential equations whose terms cannot be rewritten with the same base

Solve exponential equations of the form

for t

Recognize when there may be extraneous solutions or no solutions for exponential equations

4 0

2 years ago

Read 2 more answers

Use the points in the diagram to name the figure.

Viefleur [7K]

D) Line JK

<----->

Hope it helps :)

3 0

1 year ago