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Kryger [21]
4 years ago
11

Simplify the following expression as much as possible. (4+i)-(3-5i)(-2+5i)

Mathematics
2 answers:
strojnjashka [21]4 years ago
5 0

Answer:

-15 - 24i

Step-by-step explanation:

Ivan4 years ago
3 0

Answer:

−15−24i

Step-by-step explanation:

Hope this answers your question!

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Need help solving this math problems
AVprozaik [17]

1) If <em>x</em> is the number of years Naicul works, then the corporate job would earn him

49600<em>x</em> + 2000

dollars, while the teaching job would earn

50000<em>x</em>

dollars. Solve for <em>x</em> such that these two earnings are equal:

49600<em>x</em> + 2000 = 50000<em>x</em>

400<em>x</em> = 2000

<em>x</em> = 5

2) a) At a speed of 6.7 m/s, DJ would finish the race in

(100 m) / (6.7 m/s) ≈ 14.93 s

2) b) If DJ is given a headstart of <em>y</em> seconds, then Usain finishes the race in (9.58 + <em>y</em>) seconds. Solve for <em>y</em> such that this time matches DJ's time from part (a) :

14.93 s = (9.58 + <em>y</em>) s

<em>y</em> ≈ 5.35 s

8 0
3 years ago
What kind of function best models the data in the table? Use differences or ratios.
faltersainse [42]
Sorry i can't help with this question
4 0
3 years ago
a sack of potatoes weighs 14 pounds 9 ounces. After Wendy makes potato salad for a picnic, the sack weighs 9 pounds 14 ounces. w
Aleksandr [31]
5.76 is the correct answer to your problem
3 0
4 years ago
A Niffler is a magical creature who loves to collect shiny objects and store them in their pouch, much like a kangaroo. The amou
Fudgin [204]

Answer:

Probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.

Step-by-step explanation:

We are given that the amount a Niffler can hold in their pouch is approximately normally distributed with a mean of 25 pounds of shiny objects and a standard deviation of 6.8 pounds.

Let X = <u><em>amount a Niffler can hold in their pouch</em></u>

So, X ~ Normal(\mu=25,\sigma^{2} =6.8^{2})

The z score probability distribution for normal distribution is given by;

                                Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 25 pounds

            \sigma = standard deviation = 6.8 pounds

Now, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is given by = P(X > 32 pounds)

  P(X > 32 pounds) = P( \frac{X-\mu}{\sigma} > \frac{32-25}{6.8} ) = P(Z > 1.03) = 1 - P(Z \leq 1.03)

                                                             = 1 - 0.8485 = 0.1515

<em>The above probability is calculated by looking at the value of x = 1.03 in the z table which has an area of 0.8485.</em>

<em />

Hence, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.

4 0
3 years ago
the perimeter of a square is 80-64y units. which expression can be used to show the side lenght of one side of the square?
leonid [27]
80x by 80x up and down and 64y by 64y left and right 
5 0
3 years ago
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