1) If <em>x</em> is the number of years Naicul works, then the corporate job would earn him
49600<em>x</em> + 2000
dollars, while the teaching job would earn
50000<em>x</em>
dollars. Solve for <em>x</em> such that these two earnings are equal:
49600<em>x</em> + 2000 = 50000<em>x</em>
400<em>x</em> = 2000
<em>x</em> = 5
2) a) At a speed of 6.7 m/s, DJ would finish the race in
(100 m) / (6.7 m/s) ≈ 14.93 s
2) b) If DJ is given a headstart of <em>y</em> seconds, then Usain finishes the race in (9.58 + <em>y</em>) seconds. Solve for <em>y</em> such that this time matches DJ's time from part (a) :
14.93 s = (9.58 + <em>y</em>) s
<em>y</em> ≈ 5.35 s
Sorry i can't help with this question
Answer:
Probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.
Step-by-step explanation:
We are given that the amount a Niffler can hold in their pouch is approximately normally distributed with a mean of 25 pounds of shiny objects and a standard deviation of 6.8 pounds.
Let X = <u><em>amount a Niffler can hold in their pouch</em></u>
So, X ~ Normal(
)
The z score probability distribution for normal distribution is given by;
Z =
~ N(0,1)
where,
= population mean = 25 pounds
= standard deviation = 6.8 pounds
Now, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is given by = P(X > 32 pounds)
P(X > 32 pounds) = P(
>
) = P(Z > 1.03) = 1 - P(Z
1.03)
= 1 - 0.8485 = 0.1515
<em>The above probability is calculated by looking at the value of x = 1.03 in the z table which has an area of 0.8485.</em>
<em />
Hence, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.
80x by 80x up and down and 64y by 64y left and right