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Sliva [168]
2 years ago
15

Multiply Conjugates Using the Product of Conjugates Pattern

Mathematics
1 answer:
weeeeeb [17]2 years ago
5 0

Answer:

The product is the difference of squares is $$\left(xy-9\right)\left(xy+9\right)={{x}^2}{{y}^2}-81$$

Step-by-step explanation:

Explanation

  • The given expression is (x y-9)(x y+9).
  • We have to multiply the given expression.
  • Square the first term xy. Square the last term 9 .

$$\begin{aligned}&(x y-9)(x y+9)=(x y)^{2}-(9)^{2} \\&(x y-9)(x y+9)=x^{2} y^{2}-81\end{aligned}$$

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Ariel collected information about mockingbirds for a science project.
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3 years ago
Given: AE ≅ CE ; DE ≅ BE Prove: ABCD is a parallelogram. Parallelogram A B C D is shown. Diagonals are drawn from point A to poi
nikklg [1K]

Answer:

The proof is below

Step-by-step explanation:

Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of a parallelogram bisect each other.

In ΔACD and ΔBEC

AD=BC              (∵Opposite sides of a parallelogram are equal)

∠DAC=∠BCE       (∵Alternate angles)

∠ADC=∠CBE        (∵Alternate angles)

By ASA rule, ΔACD≅ΔBEC

By CPCT(Corresponding Parts of Congruent triangles)

AE=EC and DE=EB

Hence, AE is conruent to CE and BE is congruent to DE

6 0
2 years ago
The quadratic function f(x) has a vertex at (9, 8) and opens upward. If g(x) = 4(x − 8)2 + 9, which statement is true?
IrinaVladis [17]
G(x) would involve a translation left 1 and up 1.

g(x) is written in vertex form, which is

g(x) = a(x-h)²+k, where (h, k) is the vertex.  Since
g(x) = 4(x-8)²+9, the vertex is at (8, 9).  Comparing this to the vertex of f(x), which is at (9, 8), it is left 1 and up 1.
7 0
3 years ago
PLS HELP!!!!!!!!!!!!!!!!!! THIS IS DUE SOON AND I DONT GET IT
S_A_V [24]

Answer:

80

Step-by-step explanation:

im not sure i ever done this but 1x2=2 and 2x 40= 80

i dont know sorry im trying my bets

4 0
2 years ago
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