For the above equation and given zeros of polynomial equation we have;
y=(x+2)(x-3)(x+4)
y=(x^2+2x-3x-6)(x+4)
y=(x^2-x-6)(x+4)
y=(x^3-x^2-6x+4x^2-4x-24)
y=x^3+3x^2-10x-24
Therefore our answer is 3
Hope this helps. Any questions please just ask. Thank you.
No. 1 = x
No. 2 = 2x+7
No. 3 = x-12
Answer:
x+(2x+7)+(x-12) = 131
From there you solve to get the numbers:
34, 75 and 22
" the difference " means subtract
the difference of twice a number and 3...
2x - 3 <== ur expression
Hello :
<span>X - y = 4...(1)
x + y = 8...(2)
(1)+(2) :2x= 12
</span><span>The x-coordinate of the solution to the system shown is __6___.</span>
257 is the answer to this question
