Answer:
1/3 = 0.333333
16/33 = 0.48484848
2/11 = 0.181818
1/12 = 0.0833333
127/999 = 0.127127127
Step-by-step explanation:
divde each fraction
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
Answer:
Yes.
Step-by-step explanation:
Just like normal algebra, you factor our the common factor, in this case, 5.
Thus,
The answer is the first option: 1) 
> the quantity 
times 
minus 
all over 
The explanation is shown below:
1. To solve this problem you must pply the following proccedure:
2. Move the term
to the left member. As the variable is negative, multiply the expression by
and change the direction of the sign:
