Answer:
x^2 + y^2 = 12
Step-by-step explanation:
For a circle with the center at the origin [(h,k) is (0,0)]
use the formula:
x^2 + y^2 = r^2
In this case r is 2sqroot3.
(2sqroot3)^2 is 12.
2•2•sqrt3•sqrt3
= 4•3
= 12
So we get,
x^2 + y^2 = 12
We'll use standard labeling of right triangle ABC, C=90 degrees, legs a, b, hypotenuse c.
11.
Right triangle, cliff peak A, boat B, angle opposite cliff is B=28.9 deg. adjacent leg a=65.7 m, cliff height is leg b.
tan B = b/a
b = a tan B = 65.7 tan 28.9° = 36.3 m
12.
Similar story, boat at B, opposite b=3.5 m, rope c=12 m
sin B = b/c
B = arcsin b/c = arcsin (3.5/12) = 17.0°
13.
c=124 m, A=58°
sin A = a/c
a = c sin A = 124 sin 58 = 105.2 m
14.
That's a hypotenuse c=4-1.2 = 2.8 m to a height b=1.8m so
cos A = b/c
A = arccos b/c = arccos (1.8/2.8) = 50.0°
15.
Not a right triangle, an isosceles triangle. Half of it is a right triangle with hypotenuse one arm, c=9.8 cm and angle opposite half the base of B=62/2=31°. We're after d=2b:
sin B = b/c
b = c sin B
d = 2b = 2 c sin B = 2(9.8) sin 31 = 10.1 cm
Almost equilateral
<span><span>4−3</span>−<span><span>(2)</span><span>(<span>−6</span>)</span></span></span><span>=<span>1−<span><span>(2)</span><span>(<span>−6</span>)</span></span></span></span><span>=<span>1−<span>(<span>−12</span>)</span></span></span><span>=<span>13</span></span>
The y-value is the one on the right. Therefore, the y-value of P is 6. Following the rule, the y-value of P' is 6-16= -10.
