Answer:
w > -3
Step-by-step explanation:
2w<9+5w
Subtract 5w from each side
2w-5w<9+5w-5w
-3w <9
Divide each side by -3 remembering to flip the inequality
-3w/-3 > 9/-3
w > -3
Answer:30km/hr
Step-by-step explanation:
Total distance=294km
Speed=s
Distance=d
Time=t
First drive:
t=5
d=s x t
d=s x 5
d=5s
Second drive:
t=4
Speed is 6km/h greater than the first speed
The new speed= s+6
d=4(s+6)
Total distance=294
5s + 4(s + 6)=294
5s + 4s + 24=294
Collect like terms
5s + 4s=294 - 24
9s=270
Divide both sides by 9
9s/9=270/9
s=30
First speed=30km/hr
The class is weighted as follows:
60% Regular Tests
10% Final Exam
15% Project
15% Homework
The total weighted points possible for the class are as follows:
(100+100+100+100+100)*.6 + 100*.1 + 100*.15 + 100*.15 = 340
To calculate her individual final weighted grade we plug in her scores for each category and complete the following computation:
(92+83+77+84+82)*.6 + 88*.1 + 95*.15 + 77*.15 = 285.4
So her weighted grade percent would be 285.4/340 = 83.9% which is a B.
The angle that is supplementary to <COB is one that is next to it (in some relation)
and when you add the two angles together, they shall equal 180°.
Hope this will help
