Answer:
531
Step-by-step explanation:
Answer:
x = 7
Step by step explanation:
<em>minus</em><em> </em><em>x</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em>
6 = x -1
<em>add</em><em> </em><em>1</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em>
<em>x</em><em> </em><em>=</em><em> </em><em>7</em>
If ƒ={(5, 1),(6, 2),(7, 3),(8, 1),(9, 7)}, then the range of ƒ is {(1, 5),(2, 6),(3, 7),(1, 8),(7, 9)} {1, 2, 3, 7} {5, 6, 7, 8,
navik [9.2K]
Answer:
{1,2,3,7}
Step-by-step explanation:
The range of a relation is the set of y-values of the ordered pairs.
The given relation is:
ƒ={(5, 1),(6, 2),(7, 3),(8, 1),(9, 7)},
The set of y-values of the given ordered pairs are;
{1,2,3,7}
Therefore the range of y is {1,2,3,7}
You factor out primes from the root, for example:
root 100
you can get 10 from it, or we'll use 5
100/5=20
20/5=4
root 4= 2
because there are 2 "5" we can bring that out of the root, there are 2 "2" so we bring that out too.
When a number is taking out of a root, the 2 exact same numbers become one. in this case, there are ONE 5 and ONE 2 outside the root. then You multiply 5 and 2 together, and you get 10
