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2 years ago

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A 2-column table with 6 rows. The first column is labeled x with entries negative 4, negative 2, 0, 2, 4, 6. The second column i

s labeled f of x with entries 0, 2, 8, 2, 0, negative 2. What are all of the x-intercepts of the continuous function in the table? (0, 8) (–4, 0) (–4, 0), (4, 0) (–4, 0), (0, 8), (4, 0

1 answer:

algol132 years ago

5 0

Answer: (-4,0), (4,0)

Step-by-step explanation:

x-intercepts are when y=0.

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Solve and express to the lowest term 3 1/2 x 2 1/3 = ?

Rina8888 [55]

Answer:

8 $\frac{1}{6}$

Step-by-step explanation:

3 $\frac{1}{2}$ × 2 $\frac{1}{3}$ ( change to improper fractions )

= $\frac{7}{2}$ × $\frac{7}{3}$ ( multiply numerators and denominators )

= $\frac{7(7)}{2(3)}$

= $\frac{49}{6}$

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2 years ago

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Which correctly describes the roots of the following cubic equation x^3-5x^2+3x+9=0? A. Three real roots, each with a different

77julia77 [94]

Answer:

The correct option is C.

Step-by-step explanation:

The given cubic equation is

$x^3-5x^2+3x+9=0$

According to the rational root theorem 1 and -1 are possible rational roots of all polynomial.

At x=-1, the value of function 0. Therefore (x+1) is the factor of polynomial and -1 is a real root.

Use synthetic division to find the remaining polynomial.

$(x+1)(x^2-6x+9)=0$

$(x+1)(x^2-2(3)x+3^2)=0$

Using $(a-b)^2=a^2-2ab+b^2$

$(x+1)(x-3)^2)=0$

USe zero product property and equate each factor equal to 0.

$x=-1,x=3,x=3$

Therefore the equation have three real roots out of which the value of two roots are same.

Option C is correct.

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3 years ago

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How can you tell if a system of equations has infinite solutions?

kirill [66]

To tell if an equation has infinite solutions, the equation will be equal to each other.

For example,

x = x
x + 1 = x + 1
x - y = x - y

And so on...

And in special cases,

0x = 0
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3 years ago

ANSWER PLEASE...

liraira [26]

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Step-by-step explanation:

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2 years ago

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Write an equation in slope-intercept form of the line shown.

7nadin3 [17]

Answer:

$y = 2x - 5$

Step-by-step explanation:

Find the slope using the points, (1, -3) and (3, 1):

$slope(m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 -(-3)}{3 - 1} = \frac{4}{2} = 2$

m = 2

Find the y-intercept (b) by substituting x = 1, y = -3, and m = 2 in $y = mx + b$

$-3 = (2)(1) + b$

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Subtract 2 from both sides

$-3 - 2 = 2 + b - 2$

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$b = -5$

Plug in the value of m and b into the slope-intercept form equation, $y = mx + b$ .

Thus:

$y = 2x +(-5)$

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3 years ago