The sample proportion has an approximately normal distribution, with the mean being the population mean and the standard deviation (i.e. the standard error of the sampling proportion) equal to
SE = sqrt(p*q/n) where p is the population proportion q is 1-p, and n is the sample size.
<span>(Typically, for a confkdence interval, the sample proportion and its complement are substituted for p and q.) </span>
The margin of error will be Zc*SE, where Zc is the critical value of Z for the level of confidence required. The confidence interval, then, will be the sample proportion, plus or minus the margin of error.
For a 90% confidence interval, Zc is 1.645.
<span>So the margin of error is 1.645 * sqrt(.9*.1/400), roughly .025. So your confidence interval would be around [.875, .925]
The best and most correct answer among the choices provided by your question is the second choice or letter C which is 3%.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.</span>
(-8 + 0 / 2) (7 + 1 / 2)
(-8/2) (8/2)
(-4) (4)
Midpoint = (-4,4) [Answer]
Answer:
Write in slope-intercept form,
y =mx+bxy=4x+6
Step-by-step explanation:
Just multiply the bases and add up the exponents.
9c^6*3c^6 = 27c^6+6 = 27c^12 <- answer
