You are correct there's at least one obtuse angle
First you need to know some rules 2 numbers that are the same with coefficients divided : you differentiate those coeff
and multyplied :you sum up them
12x^8/3x^3= 4x^8-3=4x^5
20^2x=20^x*20^x
m^5*m^-7=m^5-7=m^-2
We have the following functions:
log2x=5
log10x=3
log4x=2
log3x=1
log5x=4
Let's rewrite each function to solve for x:
x=2^5=32
x=10^3=1000
x=4^2=16
x=3^1=3
x=5^4=625
Answer:
Matching each function with the solution we have:
log2x=5 ----------->32
log10x=3---------->1000
log4x=2------------>16
log5x=4------------>625
Answer:
36
Step-by-step explanation:
(-6)² = (-6) × (-6)
= +36
Answer: D:
To get system B, the second equation in system A was replaced by the sum of that equation and the first equation multiplied by 5. The solution to system B will be the same as the solution to system A.
Step-by-step explanation: