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3 years ago

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1 answer:

6 0

A.)Rachel should have 6 second class tramps. Because if you do the equation 6+6+6 you get 18 (the number of first class stamps she has)
2.)Add 6 to 18 to get your answer :)

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Please help with this question

AlladinOne [14]

Answer:

6 years

Step-by-step explanation:

10,000 = 22,400(0.88)^t

4 0

3 years ago

Given two different circles O and Q, which of the following cases presents two circles with no (zero) common tangents?

borishaifa [10]

Concentric circles because if a line is tangent to one circle, it would only intersect teh other

3 0

3 years ago

Read 2 more answers

Help please this is hard

Yuri [45]

The answer is 0,4,known ás the answer C

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3 years ago

Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function.

seropon [69]

Answer:

$h'(x)=\frac{3r^{2}}{2\sqrt{r^3+5}}$

Step-by-step explanation:

1) The Fundamental Theorem of Calculus in its first part, shows us a reciprocal relationship between Derivatives and Integration

$g(x)=\int_{a}^{x}f(t)dt \:\:a\leqslant x\leqslant b$

2) In this case, we'll need to find the derivative applying the chain rule. As it follows:

$h(x)=\int_{a}^{x^{2}}\sqrt{5+r^{3}}\therefore h'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left (\int_{a}^{x^{2}}\sqrt{5+r^{3}}\right )\\h'(x)=\sqrt{5+r^{3}}\\Chain\:Rule:\\F'(x)=f'(g(x))*g'(x)\\h'=\sqrt{5+r^{3}}\Rightarrow h'(x)=\frac{1}{2}*(r^{3}+5)^{-\frac{1}{2}}*(3r^{2}+0)\Rightarrow h'(x)=\frac{3r^{2}}{2\sqrt{r^3+5}}$

3) To test it, just integrate:

$\int \frac{3r^{2}}{2\sqrt{r^3+5}}dr=\sqrt{r^{3}+5}+C$

5 0

3 years ago

-81=7k+19=3k solve variable. include steps, also check your answer!

Bogdan [553]

Answer:

-25

Step-by-step explanation:

-81=7k+19=3k

7k-3k=-19-81

4k=-100

k=-25

3 0

3 years ago