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1 answer:

6 0

A.)Rachel should have 6 second class tramps. Because if you do the equation 6+6+6 you get 18 (the number of first class stamps she has)
2.)Add 6 to 18 to get your answer :)

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I will give brainliest to one of the correct answers.

statuscvo [17]

Answer:

1. 7/41

2. 7/15

Step-by-step explanation:

1. Probability that it is a multiple of 6 given that it is a 2 digit number: There are 7 numbers that are a multiple of 6 and are 2 digits: 12, 18, 24, 30, 36, 42, and 48. There are 41 numbers that are 2 digits. So, it is 7/41

2. Probability that it is at least 20 given that it is prime. Out of the prime numbers from 1-50, 7 of them are at least 20 and there are 15 primes in that range in total. So, it is 7/15

3 0

3 years ago

What is the answer please.... need help

mina [271]

Answer:

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

$f\left(x\right)=x^3-6x^2+3x+10$

As the highest power of the x-variable is 3 with the leading coefficients of 1.

So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

$f\left(x\right)=x^3-6x^2+3x+10$

$0=x^3-6x^2+3x+10$ ∵ $f(x)=0$

$Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

$\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

if $ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x=-1,\:x=2,\:x=5$

Therefore, the zeros of the function are:

$x=-1,\:x=2,\:x=5$

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.

8 0

3 years ago

A day can be evenly divided into 86,400 periods of 1 second; 43,200 periods of each 2 seconds; or in many other ways. In total,

Leni [432]

Answer:

96 ways

Step-by-step explanation:

Given

$Day = 86400\ seconds$