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VLD [36.1K]
3 years ago
8

-

Mathematics
1 answer:
katen-ka-za [31]3 years ago
6 0
A.)Rachel should have 6 second class tramps. Because if you do the equation 6+6+6 you get 18 (the number of first class stamps she has)
2.)Add 6 to 18 to get your answer :)
You might be interested in
I will give brainliest to one of the correct answers.
statuscvo [17]

Answer:

1. 7/41

2. 7/15

Step-by-step explanation:

1. Probability that it is a multiple of 6 given that it is a 2 digit number: There are 7 numbers that are a multiple of 6 and are 2 digits: 12, 18, 24, 30, 36, 42, and 48. There are 41 numbers that are 2 digits. So, it is 7/41

2. Probability that it is at least 20 given that it is prime. Out of the prime numbers from 1-50, 7 of them are at least 20 and there are 15 primes in that range in total. So, it is 7/15

3 0
3 years ago
What is the answer please.... need help
mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

8 0
3 years ago
A day can be evenly divided into 86,400 periods of 1 second; 43,200 periods of each 2 seconds; or in many other ways. In total,
Leni [432]

Answer:

96 ways

Step-by-step explanation:

Given

Day = 86400\ seconds

Required

Ways to divide it into period of seconds

What this question implies is to determine the total number of factors of 86400

To start with, we determine the prime factorization of 86400

To do this, we continually divide 86400 by 2; when it can not be further divided, we divide by 3, then 7, then 11...

86400/2 = 43200

43200/2=21600

21600/2=10800

10800/2=5400

5400/2= 2700

2700/2 = 1350

1350/2=675

675/3=225

225/3=75

75/3=25

25/5=5

5/5 = 1

This implies that:

86400 = 2^7 * 3^3 * 5^2

The number of factors d is the solved by:

d = (a+1)*(b+1) *(c+1)

Where

n = 2^a * 3^b * 5^c

By comparison:

a = 7

b = 3

c=2

So:

d = (7+1)*(3+1) *(2+1)

d = 8*4 *3

d = 96

<em>Hence, there are 96 total ways</em>

7 0
3 years ago
A group of 540 students are required to take a test. Of these,
snow_tiger [21]

Answer:

  1. 11
  2. 75, 210, 150, 60

6 0
3 years ago
Can someone help me with this? thank you!
ExtremeBDS [4]

Answer:

<u>242 sq. cm.</u>

Step-by-step explanation:

<u>Surface Area</u>

  • 2(LH + BH + LB)
  • 2(10 × 3 + 7 × 3 + 10 × 7)
  • 2(30 + 21 + 70)
  • 2(121)
  • <u>242 sq. cm.</u>
3 0
2 years ago
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