Solve for all of the missing angles in the rhombus below, given that m∠3 = 54°. (Round to the nearest tenth as needed.)
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the perimeter of the triangle=14.38
The coordinates of the triangle (4,1),(2,5),(1,-1);
In geometry, the perimeter of a shape is defined as the total length of its boundary.
The perimeter of the triangle is the sum of all the sides of the triangle =a+b+c (assuming a,b, and c are the sides of the triangle)
By using the distances formula find the length of the sides of the triangle:√[(x₂ - x₁)² + (y₂ - y₁)²],
where (x₁,y₁),(x₂,y₂) are the coordinates ,
a=√[(4 - 2)² + (1- 5)²] = =4.7
b=√[(2 -1)² + (5 -(-1))²]==6.08
c=√[(1 -4)² + ((-1)-1)²]==3.60
the perimeter of the triangle=a+b+c=4.7+6.08+3.60=14.38
hence ,perimeter of the triangle=14.38
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