The setup boxes in the synthetic division are (b)
<h3>How to determine the setup boxes?</h3>
The dividend is given as:
x^3 + 4x^2 + x - 6
The divisor is given as:
x - 2
Set the divisor to 0
x - 2 = 0
Solve for x
x = 2
Remove the variables in the dividend
1 + 4 + 1 - 6
Remove the arithmetic signs
1 4 1 - 6
So, the setup is:
2 | 1 4 1 - 6
Hence, the setup boxes are (b)
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Answer:
just for the points
Step-by-step explanation:
I believe that the answer is B and D
Answer:
12a³+2a²+23a+18
Step-by-step explanation:
(3a+2)(4a²-2a+9)=
12a³-6a²+27a+8a²-4a+18=
12a³+2a²+23a+18
If you need more explanation, reply to this answer.
Answer:
Is it any of the rational numbers? There are an infinite number of rational numbers. Rational numbers are any numbers that can be written as a fraction. All the integers between those two points (-2, -1, 0, etc.) are all rational. Any of the numbers between the points would be too. 1/2, 1/3, 2 1/3, etc.
Step-by-step explanation:
