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vredina [299]
3 years ago
5

10 over 20 how to make it a mixed number

Mathematics
2 answers:
deff fn [24]3 years ago
8 0
10/20 stays the same because not  an improper fraction

hope this helps you!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

VikaD [51]3 years ago
5 0

10/20 is still 10/20 because it is not an improper fraction. You can't make 10/20 as a mixed number.
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I need help!!!! :))))
zlopas [31]

Answer:

A=50.24

Step-by-step explanation:

Your diameter is 8, which makes the radius 4.

The area of a circle is

A = \pi r^{2} \\A = \pi 4^{2}

A=50.24

5 0
3 years ago
Uhhhhhmmmmmmmmmmmm wuts dis
vichka [17]

Answer:

Hey!

Step-by-step explanation:

Your answer would be 1/8

Have a nice day!♥

And ty XD

8 0
3 years ago
A swimmer is racing to the other side of the
kiruha [24]
Either B or C. They look exactly the same but I can’t tell because the photo is blurry

y intercept is 75 and x intercept is 75/2.5=30
4 0
3 years ago
Diagram shows a section of a bridge between the points A and K. The length of line segment is 640 meters. ∆ABC, ∆CDF, and ∆FJK a
Marta_Voda [28]
AK = 640
Δ ABC and ΔFJK are similar. They are small triangles.
ΔCDF is the big triangle.

640 / 2 = 320 m= CF
AC & FK= 320/2 =  160 m each

2AC = CF = 2FK
2(160) = 320 = 2(160)

BG = 20 m

20/160 = x / 320
20*320 = 160x
6400 = 160x
6400/160 = x
40 = x

Area of CDF = (40 m * 320 m)/2 = 12,800 / 2= 6,400 m²
3 0
3 years ago
A recent survey determined the IQ score of a random selection of residents of Alaska. The accompanying relative frequency distri
ycow [4]

Answer:

The class width is 20

Step-by-step explanation:

In a frequency or a relative frequency distribution the class width is calculated as the difference between the lower or upper class limits of consecutive classes. A point to note is that all the categories or classes usually have the same class width.

We use the first two classes to calculate the class width by using their respective upper limits;

Class width = 89 - 69

Class width = 20

4 0
3 years ago
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