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Nataly_w [17]
2 years ago
15

Use your understanding of transformations and key features to write the slope-intercept equation of this linear function.

Mathematics
1 answer:
sveta [45]2 years ago
8 0

Answer:

y = -2x + 5

m = -1

b = 5

Step-by-step explanation:

Hello!

Slope - Intercept Form: y = mx+b

  • m = slope
  • b = y-intercept

<h3>Slope</h3>

The slope of the line is the rate of change, or how the graph changes in y as it changes in x.

Slope can be calculated by the formula: m = \frac{y_2 - y_1}{x_2 - x_1}

We need two points on the line to get the x and y-values. I'm going to choose points (0,5) and (4,-3).

Calculate Slope

  • m = \frac{y_2 - y_1}{x_2 - x_1}
  • m = \frac{5 - (-3)}{0 - 4}
  • m = -\frac{8}{4}
  • m = -2

The slope is -2.

<h3>Y-intercept</h3>

The y-intercept of the line is where the graph touches the y-axis (x = 0). It can be found by looking at the intersection of the graph and the axis.

The intersection happens at point (0,5), so the y-intercept is 5.

<h3>Equation</h3>

We found m, the slope, to be -2 and b, the y-intercept, to be 5. We can just plug it into the equation format.

Equation: y = -2x + 5

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Step-by-step explanation:

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The radius of convergence R is 1 and the interval of convergence is (-3, -1) for the given power series. This can be obtained by using ratio test.  

<h3>Find the radius of convergence R and the interval of convergence:</h3>

Ratio test is the test that is used to find the convergence of the given power series.  

First aₙ is noted and then aₙ₊₁ is noted.

For  ∑ aₙ,  aₙ and aₙ₊₁ is noted.

\lim_{n \to \infty} |\frac{a_{n+1}}{a_{n} }| = β

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  • If β > 1, then the series diverges
  • If β = 1, then the series inconclusive

Here a_{k} = \frac{(x+2)^{k}}{\sqrt{k} }  and  a_{k+1} = \frac{(x+2)^{k+1}}{\sqrt{k+1} }

   

Now limit is taken,

\lim_{n \to \infty} |\frac{a_{n+1}}{a_{n} }| = \lim_{n \to \infty} |\frac{(x+2)^{k+1} }{\sqrt{k+1} }/\frac{(x+2)^{k} }{\sqrt{k} }|

= \lim_{n \to \infty} |\frac{(x+2)^{k+1} }{\sqrt{k+1} }\frac{\sqrt{k} }{(x+2)^{k}}|

= \lim_{n \to \infty} |{(x+2) } }{\sqrt{\frac{k}{k+1} } }}|

= |{x+2 }|\lim_{n \to \infty}}{\sqrt{\frac{k}{k+1} } }}

= |{x+2 }| < 1

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We get that,

interval of convergence = (-3, -1)

radius of convergence R = 1

Hence the radius of convergence R is 1 and the interval of convergence is (-3, -1) for the given power series.

Learn more about radius of convergence here:

brainly.com/question/14394994

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