(-3,12)
Because you substitute the 12 in for y and -3 in for x. Then you do you order of operations and you get 12=11 which is false.
Answer:
a19 = -71.74
Step-by-step explanation:
The general term of an arithmetic sequence with first term a1 and common difference d is ...
an = a1 +d(n -1)
The given 5th and 15th terms tell us ...
-3.7 = a1 +d(5 -1)
-52.3 = a1 +d(15 -1)
Subtracting the first of these equations from the second, we find ...
10d = -48.6
d = -4.86 . . . . . . divide by 10
The 19th term will be ...
a19 = a1 +d(19 -1)
Subtracting the 15th term from this, we find ...
a19 -a15 = 4d
a19 = 4d +a15 = 4(-4.86) +(-52.3)
a19 = -71.74
Answer:
Step-by-step explanation:
<h3>To prove quadrilateral is a square:</h3>
a) Slope of CB
C(-3,-1) ; B = (0,3)
![\sf = \dfrac{3-[-1]}{0-[-3]}\\\\ =\dfrac{3+1}{0+3}\\\\ = \dfrac{4}{3}](https://tex.z-dn.net/?f=%5Csf%20%3D%20%5Cdfrac%7B3-%5B-1%5D%7D%7B0-%5B-3%5D%7D%5C%5C%5C%5C%20%3D%5Cdfrac%7B3%2B1%7D%7B0%2B3%7D%5C%5C%5C%5C%20%3D%20%5Cdfrac%7B4%7D%7B3%7D)
b) D(1,-4) ; A(4,0)
![Slope \ of \ DA = \dfrac{0-[-4]}{4-1}\\](https://tex.z-dn.net/?f=Slope%20%5C%20of%20%5C%20DA%20%3D%20%5Cdfrac%7B0-%5B-4%5D%7D%7B4-1%7D%5C%5C)
Slope of CB = slope of DA
c) C(-3,-1) ; D(1 , -4)
![\sf Slope \ of \ CD =\dfrac{-4-[-1]}{1-[-3]}](https://tex.z-dn.net/?f=%5Csf%20Slope%20%5C%20of%20%5C%20CD%20%3D%5Cdfrac%7B-4-%5B-1%5D%7D%7B1-%5B-3%5D%7D)
So, CD is perpendicular to CB
d) B(0,3) ; D(1,-4)
e) C(-3,-1) ; A(4,0)
![\sf Slope \ of \ CA = \dfrac{0-[-1]}{4-[-3]}\\](https://tex.z-dn.net/?f=%5Csf%20Slope%20%5C%20of%20%5C%20CA%20%3D%20%5Cdfrac%7B0-%5B-1%5D%7D%7B4-%5B-3%5D%7D%5C%5C)
So, CA is perpendicular to BD
Answer:
48 quarts = 12 gallons
Step-by-step explanation:
