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Shalnov [3]
3 years ago
13

F(x) = 4x 3 - x 2 + 1 and g(x) = x - 1, evaluate f(g(2)).

Mathematics
1 answer:
Tpy6a [65]3 years ago
6 0

Answer:

Let f(x)=x^2 -1 and g(x)= x^2 - 2, for x has the domain of all real numbers

a. Show that (f ° g)(x)=x^4 - 4x^2 + 3.

Do we plug g(x) into f(x) ? how do we show that??

b. How could I sketch the graph of (f ° g)(x), for 0 is < or equal to x < or equal to 2.25.

Should I plug it into my calculator and just copy that?

c. The equation (f ° g)(x)=k has exactly two solutions, for x < or equal to x < or equal to 2.25. Find the possible values of k.

Step-by-step explanation:

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The on-line access computer service industry is growing at an extraordinary rate. Current estimates suggest that only 20% of the
vitfil [10]

Answer:

The probability is 0.4207

Step-by-step explanation:

The probability of a home-based computer having access to on-line services is p = 0.2 (data from the exercise)

Then, the probability of a home-based computer not having access to on-line services is p = 1 - 0.2 = 0.8

We are going to use this probability (p = 0.8) to solve the exercise.

Let's define the random variable X

X : ''Number of home-based computers not having access to on-line services''

X can be modeled as a binomial random variable

X ~ Bi(p,n)

X ~Bi(0.8,25)

Where p is the success probability and n is the number of Bernoulli independent experiments we are taking place.

We are going to count ''a success'' as a computer not having access to on-line services.

The binomial probability function is :

P(X=x)=(nCx)p^{x}(1-p)^{n-x}

Where P(X=x) is the probability of the random variable X to assume the value x

nCx is the combinatorial number define as

nCx=\frac{n!}{x!(n-x)!}

p is the success probability and n the number of Bernoulli independent experiments taking place.

In our exercise,

p=0.8\\n=25

We are looking for :

P(X>20)=P(X=21)+P(X=22)+P(X=23)+P(X=24)+P(X=25)

P(X>20)=(25C21)0.8^{21}0.2^{4}+(25C22)0.8^{22}0.2^{3}+(25C23)0.8^{23}0.2^{2}+(25C24)0.8^{24}0.2^{1}+(25C25)0.8^{25}0.2^{0}

P(X>20)=0.1867+0.1358+0.0708+0.0236+0.8^{25}

P(X>20)=0.4207

Finally, the probability of finding that more than 20 of 25 home-based computers do not have access to on-line services is 0.4207

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