Question

A normal breath takes in about 1.0 L of air. If air has an average molar mass of 28.8 g per 1 mol and has a density of 0.97 g/mL, how many molecules of air do you take in with each breath

Answer 1

Taking into account the definition of density and Avogadro's Number, you take 2.0286×10²⁵ molecules of air.

What is density

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

$density=\frac{mass}{volume}$

What is Avogadro's Number

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

Amount of molecules of air

In this case, you know that:

• Density= 0.97 $\frac{g}{mL}$
• Volume= 1 L= 1000 mL

Replacing in the definition of density:

$0.97 \frac{g}{mL}=\frac{mass}{1000 mL}$

Solving:

mass= 0.97 $\frac{g}{mL}$  ×1000 mL

mass= 970 g

Air has an average molar mass of 28.8 g per 1 mol. Then 970 grams are contained in 33.68 moles.

Now, considering the definition of Avogadro's number you can apply the following rule of three: If 1 mole of air contains 6.023×10²³ molecules, 33.68 moles contains how many molecules?

amount of molecules = (33.68 moles× 6.023×10²³ molecules)÷ 1 mole

amount of molecules= 2.0286×10²⁵ molecules

Finally, you take 2.0286×10²⁵ molecules of air.

Learn more about

density:

brainly.com/question/952755

brainly.com/question/1462554

Avogadro's Number:

brainly.com/question/11907018

brainly.com/question/1445383

brainly.com/question/1528951

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