A normal breath takes in about 1.0 L of air. If air has an average molar mass of 28.8 g per 1 mol and has a density of 0.97 g/mL
1 answer:
Taking into account the definition of density and Avogadro's Number, you take 2.0286×10²⁵ molecules of air.
<h3>What is density</h3>Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.
In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.
Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:
Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.
<h3>Amount of molecules of air</h3>In this case, you know that:
- Density= 0.97
- Volume= 1 L= 1000 mL
Replacing in the definition of density:
Solving:
mass= 0.97 ×1000 mL
<u><em>mass= 970 g</em></u>
Air has an average molar mass of 28.8 g per 1 mol. Then 970 grams are contained in 33.68 moles.
Now, considering the definition of Avogadro's number you can apply the following rule of three: If 1 mole of air contains 6.023×10²³ molecules, 33.68 moles contains how many molecules?
amount of molecules = (33.68 moles× 6.023×10²³ molecules)÷ 1 mole
<u><em>amount of molecules= 2.0286×10²⁵ molecules</em></u>
Finally, you take 2.0286×10²⁵ molecules of air.
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Avogadro's Number:
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