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kvasek [131]
2 years ago
10

Help me with this question please and thank you!!! :):)

Mathematics
1 answer:
kirill [66]2 years ago
3 0

Answer:

A intersection B = ( elements which are common in both)

= ( 2,4,7,19)

A union B = ( all the elements which are either in A or in B).

= ( 2, 4, 7 , 13, 14, 19, 20 , 3, 5, 6, 10,11, 12 , 15,17 , 18 , 19 )

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Quick I need an answer to this Queston:
fiasKO [112]

Step-by-step explanation:

-  \frac{3}{4} x + 2 \frac{1}{4 } =  \frac{1}{2} x + 1

-  \frac{3}{4} x +  \frac{9}{4}  =  \frac{1}{2} x +  \frac{2}{2}

\frac{ - 3x + 9}{4}  =  \frac{2x + 4}{4}

- 3x + 9 = 2x + 4

- 3x - 2x = 4 - 9

- 5x =  - 5

x =  \frac{ - 5}{ - 5}

x = 1

The answer is C.

6 0
1 year ago
sue has 18 sweets, tony also has 18 sweets, sue gives tony x sweets, sue eats 5 of her sweets, tony then eats half of his sweets
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7 0
3 years ago
Read 2 more answers
Solve the inequality 2-x<7​
dedylja [7]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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Identify the parent function that can be used to graph the function f(x)=-9(x+5)^2
svetoff [14.1K]

Answer:

Option a) f(x)=x^2

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8 0
3 years ago
The LCM of 2 numbers is 60 and 1 of the numbers is 7 less than the other number. What are the numbers?
Phoenix [80]
Let's represent the two numbers by x and y.  Then xy=60.  The smaller number here is x=y-7.

Then (y-7)y=60, or y^2 - 7y - 60 = 0.  Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:

discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191.  Because the discriminant is positive, this equation has two real, unequal roots, which are
        -(-7) + sqrt(191)
y = -------------------------
             -2(1)

and 

        -(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
             -2(1)

Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.


Try thinking this way:  If the LCM is 60, then xy = 60.  What would happen if x=5 and y=12?  Is xy = 60?  Yes.  Is 5 seven less than 12?  Yes.






5 0
3 years ago
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