Answer:
38 m/s
Step-by-step explanation:
We are given that
D represent Rachel's remaining distance( in meters ) as a function of time is given by
![D=-38t+220](https://tex.z-dn.net/?f=D%3D-38t%2B220)
We have to find the Rachel's speed.
We know that
![Velocity=\frac{ds}{dt}](https://tex.z-dn.net/?f=Velocity%3D%5Cfrac%7Bds%7D%7Bdt%7D)
Substitute the values then we get
![v=\frac{d(-38t+220)}{dt}=-38 m/s](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bd%28-38t%2B220%29%7D%7Bdt%7D%3D-38%20m%2Fs)
![Speed =\mid v\mid](https://tex.z-dn.net/?f=Speed%20%3D%5Cmid%20v%5Cmid)
![Speed =\mid -38\mid =38m/s](https://tex.z-dn.net/?f=Speed%20%3D%5Cmid%20-38%5Cmid%20%3D38m%2Fs)
Hence, the Rachel's speed is given by =38 m/s
Keywords:
<em>Division, quotient, polynomial, monomial
</em>
For this case we must solve a division between a polynomial and a monomial and indicate which is the quotient.
By definition, if we have a division of the form:
, the quotient is given by "c".
We have the following polynomial:
that must be divided between monomy
, then:
represents the quotient of the division:
![C (y) = \frac {65y ^ 3 + 15y ^ 2 - 25y} {5y}](https://tex.z-dn.net/?f=C%20%28y%29%20%3D%20%5Cfrac%20%7B65y%20%5E%203%20%2B%2015y%20%5E%202%20-%2025y%7D%20%7B5y%7D)
![C (y) = \frac {65y ^ 3} {5y} + \frac {15y ^ 2} {5y} - \frac {25y} {5y}](https://tex.z-dn.net/?f=C%20%28y%29%20%3D%20%5Cfrac%20%7B65y%20%5E%203%7D%20%7B5y%7D%20%2B%20%5Cfrac%20%7B15y%20%5E%202%7D%20%7B5y%7D%20-%20%5Cfrac%20%7B25y%7D%20%7B5y%7D)
![C (y) = 13y ^ 2 + 3y-5](https://tex.z-dn.net/?f=C%20%28y%29%20%3D%2013y%20%5E%202%20%2B%203y-5)
Thus, the quotient of the division between the polynomial and the monomial is given by:
![C (y) = 13y ^ 2 + 3y-5](https://tex.z-dn.net/?f=C%20%28y%29%20%3D%2013y%20%5E%202%20%2B%203y-5)
Answer:
The quotient is: ![C (y) = 13y ^ 2 + 3y-5](https://tex.z-dn.net/?f=C%20%28y%29%20%3D%2013y%20%5E%202%20%2B%203y-5)
Option: A
are there options for this question?
Answer: 0.0241
Step-by-step explanation:
This is solved using the probability distribution formula for random variables where the combination formula for selection is used to determine the probability of these random variables occurring. This formula is denoted by:
P(X=r) = nCr × p^r × q^n-r
Where:
n = number of sampled variable which in this case = 21
r = variable outcome being determined which in this case = 5
p = probability of success of the variable which in this case = 0.31
q= 1- p = 1 - 0.31 = 0.69
P(X=5) = 21C5 × 0.31^5 × 0.69^16
P(X=5) = 0.0241