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aleksandr82 [10.1K]
3 years ago
7

Which expression is equivalent to the algebraic expression below 3(-2x-1)

Mathematics
2 answers:
stiv31 [10]3 years ago
8 0

Answer:

I think you are missing the image

Step-by-step explanation:

julia-pushkina [17]3 years ago
5 0
Would be helpful if image or answer options were provided
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A plane intersecting a double-napped cone is perpendicular to the central axis. Which conic section is formed?
kkurt [141]

A) Circle

Correct on Edge 2021

7 0
3 years ago
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50 points Please help ASAP
jeyben [28]

Answer:

Im not fully sure but I think it is negative 2 and negative 3

3 0
3 years ago
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Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are locat
zavuch27 [327]

Answer:

The equation contains exact roots at x = -4 and x = -1.

See attached image for the graph.

Step-by-step explanation:

We start by noticing that the expression on the left of the equal sign is a quadratic with leading term x^2, which means that its graph shows branches going up. Therefore:

1) if its vertex is ON the x axis, there would be one solution (root) to the equation.

2) if its vertex is below the x-axis, it is forced to cross it at two locations, giving then two real solutions (roots) to the equation.

3) if its vertex is above the x-axis, it will not have real solutions (roots) but only non-real ones.

So we proceed to examine the vertex's location, which is also a great way to decide on which set of points to use in order to plot its graph efficiently:

We recall that the x-position of the vertex for a quadratic function of the form f(x)=ax^2+bx+c is given by the expression: x_v=\frac{-b}{2a}

Since in our case a=1 and b=5, we get that the x-position of the vertex is: x_v=\frac{-b}{2a} \\x_v=\frac{-5}{2(1)}\\x_v=-\frac{5}{2}

Now we can find the y-value of the vertex by evaluating this quadratic expression for x = -5/2:

y_v=f(-\frac{5}{2})\\y_v=(-\frac{5}{2} )^2+5(-\frac{5}{2} )+4\\y_v=\frac{25}{4} -\frac{25}{2} +4\\\\y_v=\frac{25}{4} -\frac{50}{4}+\frac{16}{4} \\y_v=-\frac{9}{4}

This is a negative value, which points us to the case in which there must be two real solutions to the equation (two x-axis crossings of the parabola's branches).

We can now continue plotting different parabola's points, by selecting x-values to the right and to the left of the x_v=-\frac{5}{2}. Like for example x = -2 and x = -1 (moving towards the right) , and x = -3 and x = -4 (moving towards the left.

When evaluating the function at these points, we notice that two of them render zero (which indicates they are the actual roots of the equation):

f(-1) = (-1)^2+5(-1)+4= 1-5+4 = 0\\f(-4)=(-4)^2+5(-4)_4=16-20+4=0

The actual graph we can complete with this info is shown in the image attached, where the actual roots (x-axis crossings) are pictured in red.

Then, the two roots are: x = -1 and x = -4.

5 0
3 years ago
A line passes through the point (-2,7) and had a slope of -5
Annette [7]

Answer:

a = -1

Step-by-step explanation:

The general equation for a straight line is y = mx+c, where m is the gradient/ slope, so m = -5. The first thing we need to do is find c, which we do by plugging in the x and y values that we already know: y = 7 and x = -2

7 = -5*(-2) + c

7 = 10 + c

c = 7-10 = -3

Now, we have the general equation of y = -5x -3 and we can use this to find a.

We'll treat a as x and y will be equal to 2:

2 = -5a -3

5 = -5a (Divide both sides by 5)

-a = 1 (now by -1)

a = -1

7 0
4 years ago
Read 2 more answers
The perimeter of a rectangular swimming pool is 414 meters. The length of the pool is 7 meters more than four times the width. F
PolarNik [594]

Answer:

Width = 40 meters

Length = 167 meters

Step-by-step explanation:

Let

Width of the pool = x meters

Then

Length of the pool = 4x + 7 meters

and

Perimeter =2(x+4x+7)=2(5x+7)=10x+14 meters

Hence,

10x+14=414\\ \\10x=414-14\\ \\10x=400\\ \\x=40\ meters\\ \\4x+7=4\cdot 40+7=167\ meters

5 0
3 years ago
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