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spayn [35]
2 years ago
14

Bonnie and Connie ran a total of 135 miles last week. Bonnie runs at a constant speed of 7 miles per hour, and Connie runs at a

constant speed of 5 miles per hour. If Bonnie and Connie ran for a total of 24 hours last week, how many minutes did Bonnie run
Mathematics
1 answer:
Kitty [74]2 years ago
3 0

Answer: 450 Minutes

Step-by step explanation:

135-x)/5 = hours connie runs

x/7 = hours Bonnie runs

(135-x)/5 + x/7 = 24

135-x + 5x/7 = 120

945-7x+5x = 840

-2x = -105

x = 52.5 miles = distance of Bonnie

52.5 miles / 7 m/hr = 7.5 hours = 450 minutes

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anyanavicka [17]

Remark

There is a very quick way to do this. Scan the numbers. You want 75 to be the mean, so make it so. Then figure out how many up or down you go from 75. I'll make a list of the givens.

72 - 3 72 is three down from 75 so call it - 3

75 0 That is your desired average so it adds nothing to the score.

74 -1 It is one down from 75, so call it -1

76 +1 It is one up from 75

76 +1 it is one up from 75

75 adds 0.

-3 - 1 + 1 + 1 = - 2

That comes - 2/7 which means that you need a score just under 75. So 75 will give you the right average of 75

Answer B <<<<<

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The formula for finding the area of a square that has a side length, s, is A = s^2. If a square has an area of 40 square units,
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Subtract a4 + 4a²b2 --- 264 from –3a4 + 5a%b2 + 264.
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3 years ago
1) Anna and Jason have summer jobs stuffing envelopes for two different companies. Anna earns $20 for every 400 envelopes she fi
AleksAgata [21]

Answer:

The answer is below

Step-by-step explanation:

A) i)

For Anna initially, she has $0 from making 0 envelopes. After making 400 envelopes she has $20. Let x represent the number of envelopes and y the earnings. Hence this can be represented by the points (0, 0) and (400, 20). Using the equation of a line:

y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-0=\frac{20-0}{400-0}(x-0)\\\\y=\frac{1}{20} x

The table is:

x:   200     400       600     800     1000

y:    10        20          30        40       50

ii)

For Jason initially, he has $0 from making 0 envelopes. For every 250 envelopes he has $10. Let x represent the number of envelopes and y the earnings. Hence this can be represented by the points (0, 0) and (250, 10). Using the equation of a line:

y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-0=\frac{10-0}{250-0}(x-0)\\\\y=\frac{1}{25} x

The table is:

x:   200     400       600     800     1000

y:    8         16           24        32       40

The graph is plotted using geogebra online graphing

b) From the table above we can see that Anna makes more stuffing than Jason.

c) Anna has a savings of $100. Hence this can be represented by the points (0, 100) and (250, 10). Using the equation of a line:

y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-100=\frac{20-0}{400-100}(x-0)\\\\y=\frac{1}{15} x+100

We can see from the graph that there is a y intercept at 100. That is the earnings starts from 100.

The equation of a line is given as y = mx + b, where m is the slope and b is the y intercept (initial value)

For the first graph, the slope is 1/20 and the initial value is 0 while for the second graph the slope is 1/15 and the initial value is 100

D) The line pass through (10, 10) and (100, 40), hence:

y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-10=\frac{40-10}{100-10}(x-10)\\\\y-10=\frac{1}{3} (x-10)\\\\y=\frac{1}{3}x+\frac{20}{3}

3 0
3 years ago
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