Question

A circular path 4 feet wide has an inner diameter of 550 feet. How much farther is it around the outer edge of the path than around the inner edge? Round to nearest hundredth. Use 3.14 for π.

Answer 1

Answer:

$L_c=25.12ft$

Step-by-step explanation:

From the question we are told that

Width of circular path $w_c=4ft$

Inner Diameter $d_i_n=550ft$

Outer diameter $d_{out}= 550 +2*4$  (inner diameter +  2 circular path width)

$d_{out}= 550 +8\\d_{out}= 558ft$

Generally the equation for inner circumference of the circle $C_1$ is mathematically given by

$C_1=\pi d_{in}$

$C_1=3.14*550$

$C_1=1727ft$

Generally the equation for outer circumference of the circle $C_2$ is mathematically given by

$C_2=\pi d_{out}$

$C_2=3.14*558$

$C_2=1752.12ft$

Generally the difference in length of the two circumference $L_c$ is mathematically given by

$L_c=C_2-C_1$

$L_c=1752.12-1727$

$L_c=25.12ft$