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Sauron [17]
2 years ago
14

Need help with this question

Mathematics
2 answers:
Irina18 [472]2 years ago
5 0
(4,4) is the answer I think
dexar [7]2 years ago
4 0

Answer:

(4,6)

Step-by-step explanation:

To calculate the midpoint of two points, just calculate the arithmetic mean (average) of the x and y values of the two points given. For example, it is easy to see visually that the midpoint of (2, 0) and (4, 0) is (3, 0), since (3,0) falls right in the middle of the two points. However, the way to calculate this would be to take the average of 2 and 4 (3), along with the average of 0 and 0 (0). This process gives us our new point (3, 0). In case this doesn't make sense, here is the formula for the midpoint of two points - (x1,y1) and (x2,y2):

M=(\frac{x1+x2}{2},\frac{y1+y2}{2} )

For this problem, E is (2,4) and F is (6,8). So, the midpoint would be:

(\frac{2+6}{2},\frac{4+8}{2})=(\frac{8}{2},\frac{12}{2})=(4,6)

Therefore, the midpoint is (4,6)

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1/4(x-2)+4=12 <br> 1/4(x-2)=8<br> x-2=2<br> x=4 <br> correct the error
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Step-by-step explanation:

(i) x + 3 = 0

L.H.S. = x + 3

By putting x = 3,

L.H.S. = 3 + 3 = 6 ≠ R.H.S.

∴ No, the equation is not satisfied.

(ii) x + 3 = 0

L.H.S. = x + 3

By putting x = 0,

L.H.S. = 0 + 3 = 3 ≠ R.H.S.

∴ No, the equation is not satisfied.

(iii) x + 3 = 0

L.H.S. = x + 3

By putting x = −3,

L.H.S. = − 3 + 3 = 0 = R.H.S.

∴ Yes, the equation is satisfied.

(iv) x − 7 = 1

L.H.S. = x − 7

By putting x = 7,

L.H.S. = 7 − 7 = 0 ≠ R.H.S.

∴ No, the equation is not satisfied.

(v) x − 7 = 1

L.H.S. = x − 7

By putting x = 8,

L.H.S. = 8 − 7 = 1 = R.H.S.

∴ Yes, the equation is satisfied.

(vi) 5x = 25

L.H.S. = 5x

By putting x = 0,

L.H.S. = 5 × 0 = 0 ≠ R.H.S.

∴ No, the equation is not satisfied.

(vii) 5x = 25

L.H.S. = 5x

By putting x = 5,

L.H.S. = 5 × 5 = 25 = R.H.S.

∴ Yes, the equation is satisfied.

(viii) 5x = 25

L.H.S. = 5x

By putting x = −5,

L.H.S. = 5 × (−5) = −25 ≠ R.H.S.

∴ No, the equation is not satisfied.

(ix) = 2

L.H.S. =

By putting m = −6,

L. H. S. = ≠ R.H.S.

∴No, the equation is not satisfied.

(x) = 2

L.H.S. =

By putting m = 0,

L.H.S. = ≠ R.H.S.

∴No, the equation is not satisfied.

(xi) = 2

L.H.S. =

By putting m = 6,

L.H.S. = = R.H.S.

∴ Yes, the equation is satisfied.

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