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N76 [4]
2 years ago
12

Simplify the following (-3a^2b^6)^2

Mathematics
1 answer:
JulsSmile [24]2 years ago
6 0

Answer:

9a^{4} b^{12}

(or)

9a^4b^12

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3. The standard equation of a circle (not centered at the origin) with radius r can be derived from its locus definition: The se
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Answer:

The  equation for  circle of radius r centered at the point C: (h,k) is:

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Step-by-step explanation:

To derive this equation, we need the formula for the distance between two points in the plane. If the point is given by its cartesian coordinates, we can use the Pythagorean theorem to find what the distance between the points is.

Lets say we have two points, one given by cartesian coordinates P:(x,y) and the other given by cartesian coordiantes C:(h,k)

(see diagram)

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\Delta x = x-h\\\Delta y = y-k

and by the pythagorean theorem we have:

\Delta s ^2 = \Delta x^2 + \Delta y^2

Where \Delta s is the distance between the points

Now, combining the last three equations we find:

\Delta s ^2 = (x-h)^2 + (y-k)^2

We know that the definition of a circle is the locus of points that are at a distance r from a point called the center of the circle. if we take C:(h,k) as the center of the circle, and \Delta s  =r , the last equation becomes:

r^2 = (x-h)^2 + (y-k)^2

And that is the result we wanted.

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true

Step-by-step explanation:

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