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Pani-rosa [81]
2 years ago
6

Function g is a transformation of function f.

Mathematics
1 answer:
bulgar [2K]2 years ago
4 0

The equation of function g(x) in terms of f(x) is g(x) = -3[f(x)].

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Given:

genera form of an exponential function is  y=aeᵇˣ

Now, equation for f(x) is

f(x) = e^{(log \;2)x} -2

Similarly, graph for g(x) is

g(x) = -3e^{(log \;2)x} +6

Comparing the two function a relation can  be establish

g(x) = -3[f(x)]

Learn more about Equation here:

brainly.com/question/2263981

#SPJ1

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The probability of drawing a goldfish on the first draw is 16 / ( 16 + 24 ), or 16/40, or 2/5. Supposing that the first fish drawn is actually a goldfish, then there are 15 goldfish left among 39 fish, and the probability of drawing a goldfish on the 2nd draw is 15/39, or 5/13. The (joint) probability of drawing 2 goldfish on the 1st 2 draws, without replacement, is (5/13)(2/5) = 2/13.

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3 years ago
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The answer to your questions is 3.12
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3 years ago
What is the common ratio for the geometric sequence?<br><br> 35/2, 7, 14/5, 28/25, ..…
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Step-by-step explanation:

8 0
3 years ago
A 5.1-ft-tall person walks away from a 12-ft lamppost at a constant rate of 3.9 ft/sec. What is the rate that the tip of the per
nekit [7.7K]

Answer:

6.78ft/sec

Step-by-step explanation:

From the question, dx/dt= 3.9 ft/sec

We are looking for Dy/dt

From geometry,vof this case the relationship between x and y is needed here, there is two similar triangle that exhibited by the man and the lamb

12/y= 5.1/(y-x)

Then ,cross multiply, we have

12(y-x)=5.1y

12y-12x=5.1y

12y-5.1y=12x

6.9y=12x

y=( 12/6.9)x

Differentiating implicitly the bother sides with respect to t, we have

Dy/dt= ( 12/6.9)dx/dt

But dx/dt= 3.9 ft/sec

Then Dy/dt= ( 12/6.9)× 3.9

Dy/dt=6.78ft/sec

Hence, the rate that the tip of the person's shadow moves away from the lamppost when the person is 9 ft away from the lampost is 6.78ft/sec

CHECK THE ATTACHMENT FOR THE FIQURE

6 0
3 years ago
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