We’re going to use the formula for area of a rectangle, which is length x width. We are also going to use the formula for area of a triangle which is 1/2 x base x height.

Let’s start with the rectangle under the triangle ends of the roof. They are 11mm wide, 10mm high, and there are two of them.

11 x 10 x 2 = 220

Then the other sides that are 16 x 10. There are 2 of them.
16 x 10 x 2 = 320

Then the rectangular pieces of roof, 9.7 x 16, and there are 2 of them.

9.7 x 16 x 2 = 310.4

Lastly, the triangle pieces of roof. (1/2)(base)(height), but there are 2 of them
1/2 x 11 x 8 x 2 = 88

Add up all the parts:
220 + 320 + 310.4 + 88 = 938.4 mm

6 0

2 years ago

Read 2 more answers

How many pennies would you need to make a stack that is an inch high?

satela [25.4K]

A penny is about 1/16 inch thick. So it would be 16 pennies.

3 0

4 years ago

Problems that require solving the three-dimensional schrödinger equation can often be reduced to related one-dimensional problem

dusya [7]

The wavefunction for a particle in a one-dimension box is a well-known problem, which has as a solution:

Ψ(x) = √(2/l) sin (nπx/l)

When the box has three dimensions, the general solution is simply the multiplication of the solutions for each dimension, therefore:

Ψ(x) = K · sin (n_x·π·x / l) · sin (n_y·π·y / l) · sin <span>(n_z·π·z / l)</span>

8 0

4 years ago

Which expression is equivalent to 4y^6+8y^4/2y^2, if y does not equal 0?

otez555 [7]

9514 1404 393

Answer:

The correct answer choice is marked

Step-by-step explanation:

The distributive property can be used here.

$\displaystyle \frac{4y^6+8y^4}{2y^2}=\frac{4y^6}{2y^2}+\frac{8y^4}{2y^2}=2y^{6-2}+4y^{4-2}=\boxed{2y^4+4y^2}$

3 0

3 years ago