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s2008m [1.1K]
3 years ago
11

My brain small so could you plz anwser his 6/11+ 2/ 3

Mathematics
1 answer:
Lena [83]3 years ago
4 0

Answer:

1 7/33

Step-by-step explanation:

6/11 + 2/3 --> We need a common denominator

--> 11 x 3 = 33

33 is our common denominator

6 x 3 = 18

2 x 11 = 22

18/33 + 22/33 = 40/33

Convert to a mixed number

=> 1 7/33

Thus, we have our answer.

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What are the x-intercepts of 4x^ + 8x - 5
mojhsa [17]
Assuming the exponent is supposed to be "^2" your equation will read:

4x² + 8x - 5

It must set equal to y to be a valid function and the y must be set equal to zero to find x-intercepts.

4x² + 8x - 5 = 0
4x² - 2x + 10x - 5 = 0
2x(2x - 1) + 5(2x - 1) = 0

(2x + 5)(2x - 1) = 0

Set each binomial equal to zero.

2x + 5 = 0
2x = 0 - 5
2x = - 5
Divide both sides by 2
x = - 5/2

2x - 1 = 0
2x = 0 + 1
2x = 1
x = 1/2

Your x-intercepts are x = - 5/2, 1/2 or (- 5/2, 0) and (1/2, 0)
6 0
3 years ago
Why is #2 the expression ln(2e)^3x equivalent to choice B?
motikmotik
Hello:
ln(2e^3x) =ln2+lne^3x
<span>                =ln2 +3xlne
                 = ln2+3x        .....lne=1       
               </span><span>choice B</span>
8 0
3 years ago
A rectangular tank that is 5324 ft cubed with a square base and open top is to be constructed of sheet steel of a given thicknes
marishachu [46]

Answer:

Side of 22 and height of 11

Step-by-step explanation:

Let s be the side of the square base and h be the height of the tank. Since the tank volume is restricted to 5324 ft cubed we have the following equation:

V = s^2h = 5324

h = 5324 / s^2

As the thickness is already defined, we can minimize the weight by minimizing the surface area of the tank

Base area with open top s^2

Side area 4sh

Total surface area A = s^2 + 4sh

We can substitute h = 5324 / s^2

A = s^2 + 4s\frac{5324}{s^2}

A = s^2 + 21296/s

To find the minimum of this function, we can take the first derivative, and set it to 0

A' = 2s - 21296/s^2 = 0

2s = 21296/s^2

s^3 = 10648

s = \sqrt[3]{10648} = 22

h = 5324 / s^2 = 5324 / 22^2 = 11

4 0
3 years ago
A bouncing ball reaches a height of 54 inches at its first peak, 36 inches at its second peak, and 24 inches at its third peak.
sesenic [268]

Answer:

f(x) = 54(two-thirds) Superscript x minus 1

Step-by-step explanation:

Given that:

First peak : 36 / 54=2/3

Second peak : 24 / 36 = 2/3

The common ratio here is 2/3 ; which mean each bounce height is 2/3 of previous height

Modeling this using geometric progression :

An=a1r^(n-1)

An = nth term of a geometric progression

a1=first term

r=common ratio = 2/3

n = nth term

a1=54

Substituting into the above formular :

An=54(2/3)^(n-1)

4 0
3 years ago
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Multiples of 3 are always multiples of 6.
Elena L [17]

Answer:yes 3x2=6

Step-by-step explanation:

8 0
4 years ago
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