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3 years ago

My brain small so could you plz anwser his 6/11+ 2/ 3

Mathematics

1 answer:

Lena [83]3 years ago

4 0

Answer:

1 7/33

Step-by-step explanation:

6/11 + 2/3 --> We need a common denominator

--> 11 x 3 = 33

33 is our common denominator

6 x 3 = 18

2 x 11 = 22

18/33 + 22/33 = 40/33

Convert to a mixed number

=> 1 7/33

Thus, we have our answer.

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Which of the following is INCORRECT? *

DedPeter [7]

this option is incorrect

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Step-by-step explanation:

Straight angle = 180°

Angle take 360° in one revolution

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2 years ago

X^2+4y^2=36 the lenght of the major axis is?

musickatia [10]

Answer:

Step-by-step explanation:

x² + 4y² = 36

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Stolb23 [73]

Answer:

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3 years ago

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Suppose that the terminal side of angle alphaα lies in Quadrant I and the terminal side of angle betaβ lies in Quadrant IV. If s

melamori03 [73]

Solution :

It is given that :

$\alpha$ lies in the first quadrant.

And $\beta$ lies in the fourth quadrant.

Since, $\sin \alpha = \frac{5}{13}$ and $\cos \beta = \frac{6}{\sqrt{85}}$ (given)

$\sin \alpha = \frac{5}{13}$

$\cos \alpha = \sqrt{1-\sin^2 \alpha}$

$\cos \alpha = \frac{12}{13}$

Similarly $\cos \beta = \frac{6}{\sqrt{85}}$

$\sin \beta = \sqrt{1-\cos^2 \beta}$

$\sin \beta = \sqrt{1-\frac{36}{85}}$

$-\frac{7}{\sqrt{85}}$ (IVth quadrant)

Therefore,

$\cos (\alpha + \beta) = \cos \alpha \cos \beta - \sin \alpha \sin \beta$

$=\frac{12}{13}\times \frac{6}{\sqrt{85}}-\frac{5}{13}\times \frac{-7}{\sqrt{85}}$

$= \frac{107}{13 \sqrt{85}}$

6 0

3 years ago