Answer:
// program in C++.
#include <bits/stdc++.h>
using namespace std;
int main() {
// variable
int num;
cout<<"Enter the number between 20 and 98: ";
// read number
cin >> num;
while(num<20||num>98)
{
cout<<"Wrong input!!enter number between 20-98 only:";
cin>>num;
}
cout<<"The output is: ";
while(num % 10 != num /10)
{
// print numbers.
cout<<num<<" ";
// update num.
num--;
}
// display the number.
cout<<num<<endl;;
return 0;
}
Explanation:
Read a number from user and assign it to variable "num".Check if entered number is in between 20-98 or not.If input number is less than 20 or greater than 98 then ask again to enter a number between 20-98 until user enter a valid input.Then print the countdown from input number till both the digit of number are same.
Output:
Enter the number between 20 and 98: 99
Wrong input!!enter number between 20-98 only:12
Wrong input!!enter number between 20-98 only:93
The output is: 93 92 91 90 89 88
Enter the number between 20 and 98: 77
The output is: 77
In this program, I am using the school-based grading system and the program should accept the subject and the number of students.
Program approach:-
- Using the necessary header file.
- Using the standard I/O namespace function.
- Define the main function.
- Declare the variable.
- Display enter obtain marks in 5 subjects.
- Return the value.
Program:-
//header file
#include<iostream>
//using namespace
using namespace std;
//main method
int main()
{
//declare variable
int j;
float mark, sum=0, a;
//display enter obtain marks in 5 subjects
cout<<"Enter Marks obtained in 5 Subjects: ";
for(j=0; j<5; j++)
{
cin>>mark;
sum = sum+mark;
}
a = sum/5;
//display grade
cout<<"\nGrade = ";
if(a>=91 && a<=100)
//display a1
cout<<"a1";
else if(a>=81 && a<91)
//display a2
cout<<"a2";
else if(a>=71 && a<81)
cout<<"b1";
else if(a>=61 && a<71)
cout<<"b2";
else if(a>=51 && a<61)
//display c1
cout<<"c1";
else if(a>=41 && a<51)
//display c2
cout<<"c2";
else if(a>=33 && a<41)
//display d
cout<<"d";
else if(a>=21 && a<33)
//display e1
cout<<"e1";
else if(a>=0 && a<21)
//display e2
cout<<"e2";
else
//display invalid
cout<<"Invalid!";
cout<<endl;
//return the value
return 0;
}
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