<u>Answer:</u>
The correct answer option is A. positive.
<u>Step-by-step explanation:</u>
When an exponent or a power is an even number and the base is a negative number, the value is always positive.
Suppose we have a negative base 
and a power which is even, lets say, 
so what we get is a positive value.
Therefore, a negative base with even power is always a positive value.
The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.
<h3>What is the average of five consecutive integers ending with b?</h3>
First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;
(a+a+2+a+4+a+6+a+8+a+10)/6 = b
6b=6a+30
b=a+5
Also, let the average of the consecutive intergers ending with b be denoted by; x.
(b+b-1+b-2+b-3+b-4)/5 = x
=(5b-10)/5
=b–2
The average, x=b – 2 (where b = a-5)
Ultimately, the value of the required average is; = a+5-2 = a+3.
Read more on average of integers;
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$4.5 since 1.26/7 is .14 and need 25 so it’s 4.5
