For midsegment theorem
And parallels lune are twice
So AB = YZ /2
AB = 10/2 =5
BUT AB = X–1 =5
X–1 = 5 = X = 1+5 =6
X =;6
..
MARK AS Brainliest
Answer:
<h2><u><em>
3.5 Km</em></u></h2>
Step-by-step explanation:
the length of the hypotenuse is 4 Km, it is probable that you are looking for the value of the cathetus a.
it is a right triangle and we use Pythagoras
a² = 4² - 2²
a² = 16 - 4
a² = 12
a = √12
a = 3.46 (round 3.5)
The answer is D Explanation: since the the slope is negative the x should be negative and D is the only one that has a negative X.
Answer:
for the third one 2/5 for the fourth one 3/5
Step-by-step explanation:
For the first one, I put 10/25 as a fraction and found the least common multiple, which is 5. I then simplified, and got 2/5.
For the second one, I chose 3/5 because there are 3 friends whose names end in a, and 5 friends whose names do not end in a. My theory was that I took the friends and divided them into 2 groups by most common.
hope this helps if it doesn't I will correct myself :)
Sample Response:
<em>The linear equations have the same slope, so the rate of change for each is the same. As long as the rate of change is the same, the lines will stay the same distance apart and not intersect.</em>
<em />
