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EastWind [94]
3 years ago
5

On a certain hot summer day,481 people used the public swimming pool.The daily prices are 1.25 for children and 2.25 for adults.

The receipts for admission totaled 865.25.How many children and how many adults swam at the public pool that day?
Mathematics
2 answers:
postnew [5]3 years ago
8 0

Answer: 217 children and 264 adults swam in the pool that day.

Step-by-step explanation:

Let x represent the number of children that used the public swimming pool that day.

Let y represent the number of adults that used the public swimming pool that day.

On a certain hot summer day,481 people used the public swimming pool. This means that

x + y = 481

The daily prices are 1.25 for children and 2.25 for adults. The receipts for admission totaled 865.25. This means that

1.25x + 2.25y = 865.25 - - - - - - - - -1

Substituting x = 481 - y into equation 1, it becomes

1.25(481 - y) + 2.25y = 865.25

601.25 - 1.25y + 2.25y = 865.25

- 1.25y + 2.25y = 865.25 - 601.25

y = 264

x = 481 - y = 481 - 264

x = 217

GREYUIT [131]3 years ago
5 0

Answer:

The number of children =X=217

The number of adults=264

Step-by-step explanation:

Let say the number of children are denoted by X

Then the number of adults are (481-X)

Price for children =1.25X

Price for adults=2.25(481-X)

Price for children +Price for adults=865.25

1.25X+2.25(481-X)=865.25

Solving for X:

1.25X+1082.25-2.25X=865.25

-X=865.25-1082.25

-X=-217

X=217

The number of children =X=217

The number of adults=(481-X)

The number of adults=(481-217)

The number of adults=264

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