Solving:
when you divide, you get this number: 1.56775
You have been asked to round to the tenth.
The tenth is one place right of the decimal. (currently a 5)
Look at the next place to the right. Since it is 6, we round up the tenth place by one. So our 5 in the tenth place becomes 6 (because the next digit was greater than 4)
1.6 is the final result
Answer:
![f^{-1}(x)=x^2-3](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3Dx%5E2-3)
Step-by-step explanation:
Given ![f(x)=\sqrt{x+3}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%7Bx%2B3%7D)
Let ![y=\sqrt{x+3}](https://tex.z-dn.net/?f=y%3D%5Csqrt%7Bx%2B3%7D)
Interchange x and y
![x=\sqrt{y+3}](https://tex.z-dn.net/?f=x%3D%5Csqrt%7By%2B3%7D)
Solve for y, by first squaring both sides
![x^2=y+3](https://tex.z-dn.net/?f=x%5E2%3Dy%2B3)
![x^2-3=y](https://tex.z-dn.net/?f=x%5E2-3%3Dy)
Hence
![f^{-1}(x)=x^2-3](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3Dx%5E2-3)
The last choice is correct
Answer:
24
Step-by-step explanation:
I use the Pythagoras theorem.
![\sqrt{a^{2} +b^{2} } =c^{2}](https://tex.z-dn.net/?f=%5Csqrt%7Ba%5E%7B2%7D%20%2Bb%5E%7B2%7D%20%7D%20%3Dc%5E%7B2%7D)
![4^{2}{x}6^{2} = c^{2}](https://tex.z-dn.net/?f=4%5E%7B2%7D%7Bx%7D6%5E%7B2%7D%20%3D%20c%5E%7B2%7D)
16 x 36= 576
![\sqrt{576} = 24](https://tex.z-dn.net/?f=%5Csqrt%7B576%7D%20%3D%2024)
Step-by-step explanation:
8.35 < 3x + 18.75
3x + 18.75 > 8.35
3x > 8.35 - 18.75
3x > -10.4
x > -3.47