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3 years ago

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Mathematics

2 answers:

irina1246 [14]3 years ago

4 0

Fhjjnhhcgcfcg xftfcgcgc :dphbnjjn

Feliz [49]3 years ago

3 0

Answer:

nsjsnnf rns BTW 100+23=123

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Answer:

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9 times the sum of 8 and y

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Answer:

9(8+y)

Step-by-step explanation:

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Jake tosses a coin up in the air and lets it fall to the ground. The equation that models the height (in feet) and time (in seco

adoni [48]

Answer:

The maximum height of coin Jake tosses is 15 feet.

Step-by-step explanation:

Given Jake tosses a coin up in the air

and the height of coin is model by h(t)= $(-16)t^{2} +24t+6$

To find height of the coin when Jake tosses it:

When a coin is in the hand of Jake, time t=0

Height of coin is h(t)= $(-16)t^{2} +24t+6$

h(0)= $(-16)(0)^{2} +24(0)+6$

h(0)=6 feet.

Therefore, Height of coin at time t=0 is 6.

For maximum height of the coin,

h(t)= $(-16)t^{2} +24t+6$

Differentiating both side,

$\frac{d}{dt}h(t)=\frac{d}{dt}[(-16)t^{2} +24t+6]$

$\frac{d}{dt}h(t)=\frac{d}{dt}[(-32)t+24]$

$\frac{d}{dt}h(t)=0$

$\frac{d}{dt}[(-32)t+24]=0$

t= $\frac{24}{32}$

t= $\frac{3}{4}$

t=0.75

Now,

h(t)= $(-16)t^{2} +24t+6$

h(0.75)= $(-16)(0.75)^{2} +24(0.75)+6$

h(0.75)=15 feet.

The maximum height of coin jake tosses is 15 feet.

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3 years ago

Find the midpoint M of the line segment joining the points S = (-6, 4) and T = (0, -8).

AfilCa [17]

Step-by-step explanation:

the coordinates of the midpoint are the mean value between the coordinates.

M = ((-6 + 0)/2, (4 + -8)/2) = (-6/2, -4/2) = (-3, -2)

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2 years ago

While visiting the Albert Michelson exhibit at Clark University, you notice that a chandelier (which looks remarkably like a sim

labwork [276]

Answer:

a) $F=0.16Hz$

b) $\omega=1rad/s$

c) $L=9.54m$

d) $g=9.46m/s^2$

Step-by-step explanation:

From the question we are told that:

Time $T =6.2$

Generally the equation for Frequency F is mathematically given by:

$F=\frac{1}{T}$

$F=\frac{1}{6.2}$

$F=0.16Hz$

Generally the equation for Frequency F is mathematically given by:

$\omega=2\pi f$

$\omega=2*314* 0.16$

$\omega=1rad/s$

Generally the equation for Length of Chandelier L is mathematically given by:

Since

$T=2*3.142\sqrt{\frac{L}{g}}$

Therefore

$L=\frac{gT^2}{4 \pi^2}$

$L=\frac{9.8*(6.2)^2}{4 \pi^2}$

$L=9.54m$

Since

Michelson exhibit except this one swings back and forth 0.11 seconds slower

Therefore

$T'=T+0.11$

$T'=6.31$

Generally the equation for acceleration due to gravity g is mathematically given by:

$g = \frac{4\pi ^2L}{( T')}^2$

$g = \frac{4\pi ^2L\*9.54}{( 6.31 s )}^2$

$g=9.46m/s^2$

4 0

3 years ago