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bixtya [17]
3 years ago
7

Factor the trinomial completely. x^2-5x-24

Mathematics
1 answer:
Vikki [24]3 years ago
4 0
The answer is:  " (x − 8) (x + 3) " .
__________________________________________________________
  " (x − 8) (x + 3) " are the factors of:  " x² − 5x − 24 " .
_________________________________________________________
Explanation:
__________________________________________________________

Given:  "x² − 5x − 24 " ;  Factor this "trinomial" expression completely.

We notice the "-5x" and the "-24 .

What factors of "-24" add up to "-5" ?

-1 + 24 ? No.

-24 + 1 ? no. 

-12 + 2 = -10? No.

12 + (-2) = 12 - 2 = 10 ? No.

-3 + 8 = 5 ? No.

-8 + 3 = -5 ?  Yes! 

So:   " (x − 8) (x + 3) " are the factors of:  " x² − 5x <span>− 24 " .
______________________________________________________ </span>
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Which values are in the solution set of the compound inequality? Check all that apply. 4(x + 3) ≤ 0 or x + 1 &gt; 3 –6 –3 0 3 8
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we have

4(x + 3) \leq 0 -------> inequality 1

or

x + 1 > 3 -------> inequality 2

we know that

In this system of inequalities, for a value to be the solution of the system, it is enough that it satisfies at least one of the two inequalities.

let's check each of the values

<u>case 1)</u> x=-6

<u>Substitute the value of x=-6 in the inequality 1</u>

4(-6 + 3) \leq 0

4(-3) \leq 0

-12 \leq 0 -------> is ok

The value of x=-6 is a solution of the compound inequality-----> It is not necessary to check the second inequality, because the first one satisfies

<u>case 2)</u> x=-3

<u>Substitute the value of x=-3 in the inequality 1</u>

4(-3 + 3) \leq 0

4(0) \leq 0

0 \leq 0 -------> is ok

The value of x=-3 is a solution of the compound inequality-----> It is not necessary to check the second inequality, because the first one satisfies

<u>case 3)</u> x=0

<u>Substitute the value of x=0 in the inequality 1</u>

4(0 + 3) \leq 0

4(3) \leq 0

12 \leq 0 -------> is not ok

<u>Substitute the value of x=0 in the inequality 2</u>

0 + 1 > 3

1 > 3 --------> is not ok

The value of x=0 is not a solution of the compound inequality

case 4) x=3

<u>Substitute the value of x=3 in the inequality 1</u>

4(3 + 3) \leq 0

4(6) \leq 0

24 \leq 0 -------> is not ok

<u>Substitute the value of x=3 in the inequality 2</u>

3 + 1 > 3

4 > 3 --------> is ok

The value of x=3 is a solution of the compound inequality

case 5) x=8

<u>Substitute the value of x=8 in the inequality 1</u>

4(8 + 3) \leq 0

4(11) \leq 0

44 \leq 0 -------> is not ok

<u>Substitute the value of x=8 in the inequality 2</u>

8 + 1 > 3

9 > 3 --------> is ok

The value of x=8 is a solution of the compound inequality

<u>case 6)</u> x=10

<u>Substitute the value of x=10 in the inequality 1</u>

4(10 + 3) \leq 0

4(13) \leq 0

52 \leq 0 -------> is not ok

<u>Substitute the value of x=10 in the inequality 2</u>

10+ 1 > 3

11 > 3 --------> is ok

The value of x=10 is a solution of the compound inequality

therefore

<u>the answer is</u>

[-6,-3,3,8,10]

7 0
3 years ago
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