1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Harrizon [31]
2 years ago
7

Please help

Mathematics
1 answer:
sveta [45]2 years ago
4 0

Based on the data given on the number pattern, 4 + 5 = 180

<h3>Number pattern</h3>

7 + 9 = 254016

3 + 7 = 7779240

5 + 8 = 2496000

7 + 9 = (7 × 9)^|7-9| × (7 + 9) × |7 - 9)

= 69² × 16 × 2

= 4761 × 16 × 2

= 254,016

3 + 7 = (3×7)^|3-7| × (3+7) × |3-7|

= 21⁴ × 10 × 4

= 194,481 × 10 × 4

= 7,779,240

So,

4 + 5 = (4×5)^|4-5| × (4+5) × |4-5|

= 20¹ × 9 × 1

4 + 5 = 180

Learn more about pattern of numbers:

brainly.com/question/6561461

#SPJ1

You might be interested in
6(40 - 2b) – 2195-70)
Naddika [18.5K]

Answer:

B= -6,255

Step-by-step explanation:

7 0
3 years ago
A triangle has side lengths of (1.2u+1.8v)(1.2u+1.8v) centimeters, (6.5u+8.7w)(6.5u+8.7w) centimeters, and (5.8w-6.9v)(5.8w−6.9v
Komok [63]

Answer:

7.7u - 5.1v + 14.5w

Step-by-step explanation:

Given length:

Side A = (1.2u+1.8v) centimeters,

Side B = (6.5u+8.7w) centimeters

Side C = (5.8w-6.9v) centimeters

Perimeter of a triangle = side A + side B + side C

= (1.2u+1.8v) + (6.5u+8.7w) + (5.8w-6.9v)

= 1.2u + 1.8v + 6.5u + 8.7w + 5.8w - 6.9v

Collect like terms

= 1.2u + 6.5u + 1.8v - 6.9v + 8.7w + 5.8w

= 7.7u - 5.1v + 14.5w

Therefore, the perimeter of the triangle is 7.7u - 5.1v + 14.5w

5 0
4 years ago
A large box contains 10,000 ball bearings. A random sample of 120 is chosen. The sample mean diameter is 10 mm, and the standard
ser-zykov [4K]

Answer:

Option a) A 95% confidence interval for the mean diameter of the 120 bearings in the sample is 10 \pm 1.96\displaystyle\frac{0.24}{\sqrt{120}}.

Step-by-step explanation:

We are given the following information in the question:

Sample size, n = 120

Sample mean = 10 mm

Standard Deviation = 0.24 mm

Formula:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

10 \pm 1.96\displaystyle\frac{0.24}{\sqrt{120}}

Hence, the correct interpretation for the confidence interval is given by option a).

A 95% confidence interval for the mean diameter of the 120 bearings in the sample is 10 \pm 1.96\displaystyle\frac{0.24}{\sqrt{120}}.

We have to consider the factor of sampling of 120 ball bearings from a population of 10,000 ball bearings.

8 0
3 years ago
This table shows some values of an exponential function. x у 01.25 1 2.50 25 3 10 What is the function?​
Helen [10]

Answer:

y= 1.25(2)^{x}

Step-by-step explanation:

y= 1.25(2)^{x}

For x=0

y= 1.25(2)^{0} = 1.25

For x=1

y= 1.25(2)^{1} = 1.25(2)=2.5

For x=2

y= 1.25(2)^{2} = 1.25(4)=5

For x=3

y= 1.25(2)^{3} = 1.25(8)=10

7 0
3 years ago
PLEASE HELP FOR 10 POINTS what is the length of PM
Nataly_w [17]

Answer:

D

Step-by-step explanation:

The figures are the same just flipped. We can tell AD=NM ON=AB, BC=OP. Thus DC =MP

DC has the length of 6 and because MP is congruent to DC it also has 6.

8 0
3 years ago
Other questions:
  • Which ordered pair is the best estimate for the solution of the system of equations?
    15·1 answer
  • ....??help??............
    13·2 answers
  • At West High School, 16% of the student population is taking a calculus course, 11% is taking a physics course, and 4% is taking
    13·2 answers
  • Three is added to a number ,and then the sum is multiplied by 4 the result is 16
    11·1 answer
  • 2)
    10·1 answer
  • Plzzzzzzzzzzzzzzzzzzzz
    9·1 answer
  • Find (f o g)(0) *serious answers only*
    7·1 answer
  • Nick (austin?) spends $12 to buy 16 oranges how much dose Nick (austin?) spend per orange
    13·2 answers
  • In ΔFGH, f = 960 inches, g = 380 inches and h=820 inches. Find the measure of ∠F to the nearest degree.
    12·1 answer
  • Whats the answer giving brainliest
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!