Answer: y-intercept: (0,-6)
Answer:
Part A
The bearing of the point 'R' from 'S' is 225°
Part B
The bearing from R to Q is approximately 293.2°
Step-by-step explanation:
The location of the point 'Q' = 35 km due East of P
The location of the point 'S' = 15 km due West of P
The location of the 'R' = 15 km due south of 'P'
Part A
To work out the distance from 'R' to 'S', we note that the points 'R', 'S', and 'P' form a right triangle, therefore, given that the legs RP and SP are at right angles (point 'S' is due west and point 'R' is due south), we have that the side RS is the hypotenuse side and ∠RPS = 90° and given that
=
, the right triangle ΔRPS is an isosceles right triangle
∴ ∠PRS = ∠PSR = 45°
The bearing of the point 'R' from 'S' measured from the north of 'R' = 180° + 45° = 225°
Part B
∠PRQ = arctan(35/15) ≈ 66.8°
Therefore the bearing from R to Q = 270 + 90 - 66.8 ≈ 293.2°
Answer:
y=3x+1, or the second option
Step-by-step explanation:
We can see on the graph the line converges with the y-axis at (0, 1), so we can cross out the last two answers. Then we can also see that the slope is 3 on the graph and an equation that has x^2 must be a parabola. The answer is then narrowed down to the second option.
Answer:
408.46cm^2
Step-by-step explanation:
Given data
Height= 13cm
Diameter= 10cm
Radius= D/2= 10/2= 5cm
The area of the curved surface will be = 2πr × h = 2πrh
substitute
Area of the curved surface = 2πrh= 2*3.142*5*13
Area of the curved surface = 2πrh= 408.46cm^2
Hence the area of the curve surface is 408.46cm^2