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Fittoniya [83]
2 years ago
7

Please help me write an equation for this polynomial graphed

Mathematics
2 answers:
oksian1 [2.3K]2 years ago
3 0

The equation for this polynomial graphed will be P(x) = a(x + 2)(x + 1)(x – 3)³.

<h3>What is polynomial?</h3>

A polynomial expression is an algebraic expression with variables and coefficients.

The graph of the polynomial is given below.

From the graph, the roots of the polynomial will be -2, -1, and 3.

Then the factor of the polynomial will be

(x + 2), (x + 1), and (x – 3)

Then the polynomial will be

P(x) = a(x + 2)(x + 1)(x – 3)³

More about the polynomial link is given below.

brainly.com/question/17822016

#SPJ1

Sedaia [141]2 years ago
3 0

The equation of the given polynomial is f(x)=(x+2)(x+1)(x-3).

here we have given the graph of the

The roots of the given polynomial is

x=-2,x=-1 and x=3

<h3>What is the polynomial?</h3>

A polynomial is an expression consisting of indeterminates and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables.

Therefore the equation of the polynomial is

f(x)=(x+2)(x+1)(x-3)

Therefore the equation of the given polynomial is f(x)=(x+2)(x+1)(x-3).

To learn more about the polynomial visit:

brainly.com/question/2833285

#SPJ1

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11/ 42 Marks
amm1812

Answer:

(a)x=128 degrees

(b)\angle APD\neq 116^\circ

Step-by-step explanation:

\angle ABD+\angle CBD =180^\circ$ (Linear Postulate)\\\angle ABD+116^\circ =180^\circ\\\angle ABD=180^\circ-116^\circ\\\angle ABD=64^\circ

(a) Now:

\angle AOD=2 \times \angle ABD$ (Angle at the centre is twice the  angle at the circumference)\\x=2 \times 64^\circ\\x=128^\circ

(b)

\angle APD=2 \times \angle ABD$ (Inscribed Angle Theorem)\\\angle APD=2 \times 64^\circ\\ \angle APD=128^\circ

\angle APD\neq 116^\circ

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