Answer:
C. 
General Formulas and Concepts:
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Derivative Rule [Product Rule]: ![\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bf%28x%29g%28x%29%5D%3Df%27%28x%29g%28x%29%20%2B%20g%27%28x%29f%28x%29)
Trig Derivatives
Logarithmic Derivatives
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>

<u>Step 2: Differentiate</u>
- Derivative Rule [Product Rule]:
![\displaystyle f'(x) = \frac{d}{dx}[ln(x)]cos(x) + ln(x)\frac{d}{dx}[cos(x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%27%28x%29%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bln%28x%29%5Dcos%28x%29%20%2B%20ln%28x%29%5Cfrac%7Bd%7D%7Bdx%7D%5Bcos%28x%29%5D)
- Logarithmic Derivative:
![\displaystyle f'(x) = \frac{1}{x}cos(x) + ln(x)\frac{d}{dx}[cos(x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%27%28x%29%20%3D%20%5Cfrac%7B1%7D%7Bx%7Dcos%28x%29%20%2B%20ln%28x%29%5Cfrac%7Bd%7D%7Bdx%7D%5Bcos%28x%29%5D)
- Trig Derivative:
![\displaystyle f'(x) = \frac{1}{x}cos(x) + ln(x)[-sin(x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%27%28x%29%20%3D%20%5Cfrac%7B1%7D%7Bx%7Dcos%28x%29%20%2B%20ln%28x%29%5B-sin%28x%29%5D)
- Simplify:

Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation
Book: College Calculus 10e
F(x)= 2x-6
Y=Mx+b
B= y intercept= -6
M= how many times it went up so 2 times
Hope this helped :))
We have the following limit:
(8n2 + 5n + 2) / (3 + 2n)
Evaluating for n = inf we have:
(8 (inf) 2 + 5 (inf) + 2) / (3 + 2 (inf))
(inf) / (inf)
We observe that we have an indetermination, which we must resolve.
Applying L'hopital we have:
(8n2 + 5n + 2) '/ (3 + 2n)'
(16n + 5) / (2)
Evaluating again for n = inf:
(16 (inf) + 5) / (2) = inf
Therefore, the limit tends to infinity.
Answer:
d.limit does not exist
Answer:
im pretty sure its c
Step-by-step explanation: