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alexandr402 [8]
2 years ago
11

Denver has a current temperature of -5°, while Barcelona has a current temperature of 54°. What is the difference in temperature

between Denver and Barcelona?
Mathematics
1 answer:
irga5000 [103]2 years ago
7 0

Answer:

59°

Step-by-step explanation:

Difference=54-(-5)

=54+5=59

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Trinity collected 2,400 grams of pennies in a fundraiser. Each penny has a mass of 2.5 grams. How much money did Trinity raise?
sp2606 [1]

Answer:

960

Step-by-step explanation:

6 0
3 years ago
Marissa and Callie both have babysitting jobs. Marissa charges $19 plus $1.50 per hour. Callie charges $15 plus $2.75 per hour.
aliya0001 [1]

Answer:

4 hours

Step-by-step explanation:

Write an equation

19 +1.5x < 15+2.75x

Subtarct 15 on both sides

4+1.5x<2.75x

subtract 1.5x on both sides

4< 1.25x

Divide 1.25 on each side

3.2<X

Since they on,y charge per hour so 4 hours

3 0
3 years ago
Read 2 more answers
If a track has 219 miles and takes 108 minutes to get there. Is the average speed 104 miles per hour
Tema [17]

Answer:

<em><u>122 miles per hour</u></em><em><u>.</u></em><em><u> </u></em>

Step-by-step explanation:

Time:108 min ÷60 =1.8 hours

Speed = distance /time = 219/1.8 =122 miles per hour.

Hope this helps..

8 0
3 years ago
Read 2 more answers
How do you count by 8s and 7s
galben [10]

Answer:

just add 8+8+8 until you get to the number u want/need and the same with 7. Or you can multiply.

8x1=8

7x1=7

8x3=24        (8+8+8=24)

7x3=21         (7+7+7=21)

etc.


Hope it helps!

7 0
3 years ago
Calculate pt3 such that a line from pt1 to pt3 is perpendicular to the line from pt1 to pt2, and the distance between pt1 and pt
Leni [432]
Let the point_1 = p₁ = (1,4)
and      point_2 = p₂ = (-2,1)
and      Point_3 = p₃ = (x,y)

The line from point_1 to point_2 is L₁ and has slope = m₁
The line from point_1 to point_3 is L₂ and has slope = m₂
m₁ = Δy/Δx = (1-4)/(-2-1) = 1
m₂ = Δy/Δx = (y-4)/(x-1)
L₁⊥L₂ ⇒⇒⇒⇒ m₁ * m₂ = -1
∴ (y-4)/(x-1) = -1 ⇒⇒⇒ (y-4)= -(x-1)
(y-4) = (1-x) ⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒ equation (1)

The distance from point_1 to point_2 is d₁
The distance from point_1 to point_3 is d₂
d = \sqrt{Δx^2+Δy^2}
d₁ = \sqrt{(-2-1)^2+(1-4)^2}
d₂ = \sqrt{(x-1)^2+(y-4)^2}
d₁ = d₂
∴ \sqrt{(-2-1)^2+(1-4)^2} = \sqrt{(x-1)^2+(y-4)^2} ⇒⇒ eliminating the root
∴(-2-1)²+(1-4)² = (x-1)²+(y-4)²
 (x-1)²+(y-4)² = 18
from equatoin (1)  y-4 = 1-x
∴(x-1)²+(1-x)² = 18            ⇒⇒⇒⇒⇒ note: (1-x)² = (x-1)²
2 (x-1)² = 18
(x-1)² = 9
x-1 = \pm \sqrt{9} = \pm 3
∴ x = 4 or x = -2
∴ y = 1 or y = 7

Point_3 = (4,1)  or  (-2,7)












8 0
3 years ago
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