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rusak2 [61]
2 years ago
8

92÷9−5=913 find value of p

Mathematics
1 answer:
Vlad [161]2 years ago
3 0

Answer:

which p? there isn't any p in above equation

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Terrence took a total of 16 pages of notes during 8 hours of class. In all, how many hours will
r-ruslan [8.4K]
16 pages/8 hrs

2 pages/ he

18/2=9

18 pages/9 hrs

9 hours is your answer.
3 0
2 years ago
What is 90% of 20????
pickupchik [31]

Answer:

18

Step-by-step explanation:

Multiply 20 by 0.90 (that is 90%)

18 is the answer

Hope this helps :)

6 0
3 years ago
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Given each of the following areas, what would be the radius of each circle? a. A = 530.66 m2 b. A = 907.46 sq. ft. c. A = 379.94
ra1l [238]
Area for a circle is A= \pi r^2.  We will fill in each area and then solve for the radius.  530.66m^2= \pi r^2 and \frac{530.66m^2}{3.14}=r^2.  ∴169=r^2 and r = 13.  For b, 907.46ft^2= \pi r^2 and \frac{907.46ft^2}{3.14}=r^2.  289=r^2, ∴ r = 17.  For c, 379.94mi^2= \pi r^2, and \frac{379.94mi^2}{3.14}=r^2.  ∴, 121=r^2 and r = 11.  For d, 1962.5cm^2= \pi r^2, and \frac{1962.5cm^2}{3.14}=r^2.  ∴, 625=r^2 so r = 25.  And there you have it!
3 0
3 years ago
Homer is giving some cookies to each of
Stells [14]

Answer:

7 cookies

Step-by-step explanation:

We have 3 brothers

First , Second, Third

Let the total number cookies be represented by A

1 cookie = 1

Working backwards, we start from the third brother

If we work backwards

It means he gave everything away

We start from the youngest

He was given 1/2 of what was left and 1/2 a cookie

This means,

1/2 + 1/2 = 1

The second brother

He got half of what is left and 1/2 a cookies

Half of what is left from brother

= What the youngest brother got + 1/2 + 1/2 a cookie

= 1 + 1/2 + 1/2

= 1.5 + 1/2

= 2 cookies

For the first brother

He got 1/2 of the cookies + 1/2 cookie

= 1.5 × 2 + 1/2 + 1/2 cookies

= 3 1/2 + 1/2

= 4 cookies

The first brother got 4 cookies

The second brother got 2 cookies

The third broth got 1 cookies

3 0
3 years ago
If the original square had a side length of
irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas  in the attached figure N 3, and the trinomial is x^{2} +11x+28

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

Length=(x+4)\ in

width=(x+7)\ in

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas  in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

A1=(x)(x)=x^{2}\ in^2

A2=(4)(x)=4x\ in^2

A3=(x)(7)=7x\ in^2

A4=(4)(7)=28\ in^2

The total area of the second rectangle is the sum of the four areas

A=A1+A2+A3+A4

State the product of (x+4) and (x+7) as a trinomial

(x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28

Part c) If the original square had a side length of  x = 2 inches, then what is the area of the  second rectangle?

we know that

The area of the second rectangle is equal to

A=A1+A2+A3+A4

For x=2 in

substitute the value of x in the area of each portion

A1=(2)(2)=4\ in^2

A2=(4)(2)=8\ in^2

A3=(2)(7)=14\ in^2

A4=(4)(7)=28\ in^2

A=4+8+14+28

A=54\ in^2

Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in

We have that

The trinomial is

A(x)=x^{2} +11x+28

For x=2 in

substitute and solve for A(x)

A(2)=2^{2} +11(2)+28

A(2)=4 +22+28

A(2)=54\ in^2 ----> verified

therefore

The trinomial represent the total area of the second rectangle

7 0
3 years ago
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