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Angelina_Jolie [31]
2 years ago
11

8. The bottom part of this block is a rectangular prism. The top part is a square pyramid. You want to

Mathematics
1 answer:
Travka [436]2 years ago
3 0

Answer:

Amount of paper need = 140 cm²

Step-by-step explanation:

Given:

Length of rectangular prism = 5 cm

Width of rectangular prism = 5 cm

Height of rectangular prism = 4 cm

Base of triangular side = 5cm

Height of triangular side = 6 cm

Find:

Amount of paper need

Computation:

Amount of paper need = Curved surface area of rectangular prism +  Curved surface area of square pyramid

Amount of paper need = 2h(l + b) + 4[Area of triangle]

Amount of paper need = 2h(l + b) + 4[(1/2)(b)(h)]

Amount of paper need = (2)(4)(5 + 5) + 2[(5)(6)]

Amount of paper need = (8)(10) + 2[30]

Amount of paper need = 80 + 60

Amount of paper need = 140 cm²

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The top graph
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3 years ago
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8. The Last Supper
Salsk061 [2.6K]

The number of possible seats is an illustration of permutation

There are 1728 possible sitting arrangements

<h3>How to determine the number of seats</h3>

From the question, we have the following highlights:

  • Chris can only take 1 seat (i.e. the central seat)
  • Jo can take 2 seats (i.e. the seats adjacent the central seat)
  • Alex, Barb and Dave can take 3! number of seats
  • Eddie, Fred, and Gareth can take 3! number of seats on the right of Chris.
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So, the number of sitting arrangement is:

n = 1 * 2 * 3! * 3! * 4!

Evaluate the product

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Hence, there are 1728 possible sitting arrangements

Read more about permutation at:

brainly.com/question/12468032

7 0
2 years ago
2.
abruzzese [7]

Answer:

  a) 30 kangaroos in 2030

  b) decreasing 8% per year

  c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo

Step-by-step explanation:

We assume your equation is supposed to be ...

  P(t) = 76(0.92^t)

__

a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30

In the year 2030, the population of kangaroos in the province is modeled to be 30.

__

b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.

The population is decreasing by 8% each year.

__

c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.

  P(100) = 75(0.92^100) = 76(0.0002392)

  P(100) ≈ 0.0182, about 1/55th of a kangaroo

5 0
3 years ago
Write a number or expression in each blank space to create true equations.
Rina8888 [55]

Answer:

7(3+5)=7(3)+7(5)\\15-10=5(3-2)

Step-by-step explanation:

Both expressions are examples of the <em>distributive property</em>, which basically says "if I have <em>this </em>many groups of some size and <em>that</em> many groups of the same size, I've got <em>this </em>+ <em>that</em> groups of that size altogether."

To give an example, if I've got <em>3 groups of 5 </em>and <em>2 groups of 5</em>, I've got 3 + 2 = <em>5 groups of 5 </em>in total. I've attached a visual from Math with Bad Drawings to illustrate this idea.

Mathematically, we'd capture that last example with the equation

5(3)+5(2)=5(3+2). We can also read that in reverse: 3 + 2 groups of 5 is the same as adding together 3 groups of 5 and 2 groups of 5; both directions get us 8 groups of 5. We can use this fact to rewrite the first expression like this: 7(3+5)=7(3)+7(5).

This idea extends to subtraction too: If we have 3 groups of 4 and we take away 1 group of 4, we'd expect to be left with 3 - 1 = 2 groups of 4, or in symbols: 4(3)-4(1)=4(3-1)=4(2). When we start with two numbers like 15 and 10, our first question should be if we can split them up into groups of the same size. Obviously, you could make 15 groups of 1 and 10 groups of 1, but 15 is also the same as <em>3 groups of 5</em> and 10 is the same as <em>2 groups of 5</em>. Using the distributive property, we could write this as 15-10=3(5)-2(5)=5(3-2), so we can say that 15-10=5(3-2).

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Answer:

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