Three main methods come to mind: Substitution method, Elimination method, Matrix row-reduction.The first two methods are taught in early grades in most high schools. Matrix row-reduction is taught in senior years in high school, or more likely, in the early years of a university math or science program.
The given statement is false because it isn't an empty set!
<u>Step-by-step explanation:</u>
We have following sets of inequalities:
From 
we get ,
Therefore solution set is x=2.
Now, for 
we get ,
Therefore solution set is x>2.
For 
we get ,
Therefore solution set is x<2.
Now, the union of x=2, x<2 & x>2 is -∞<x<∞. i.e. all possible values of x. And so above statement is false because it isn't an empty set!
Answer:
$26.02
Step-by-step explanation:
Let the price of a skirt be A and that of coat be B
Iilly bought 6 skirts and 5 coats for a total of $452.62
That’s
6A + 5B = 452.62
Also, Lilly’s sister bought 3 skirts and 5 coats for $289.36
That’s
3A + 5B = 289.36
We now have two equations
1 . 6A + 5B = 452.62
2. 3A + 5B = 289.36
Subtract equation two from equation one
We have
3A = 163.26
Divide both sides by 3
3A/3 = 163.26/3
A = 54.42
A = $54.42
Now substitute 54.42 for A in either equations to get B the price of a coat
Using equation one, we have
6A + 5B = 452.62
6 x 54.42 + 5B = 456.62
326.52 + 5B = 456.62
Subtract 326.52 from both sides
326.52 - 326.52 + 5B = 456.62 - 326.52
5B = 130.1
Divide both sides by 5
5B/5 = 130.1/5
B = 26.02
= $26.02
A coat cost $26.02
Answer:
We need a reference to do this with but i would say 6/16
Step-by-step explanation:
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