There are 
ways of picking 2 of the 10 available positions for a 0. 8 positions remain.
There are 
ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's 
way of doing that.
So we have
The last expression has a more compact form in terms of the so-called multinomial coefficient,
Answer:
-6
Step-by-step explanation:
So consectuve even numbers
we know that one even number plus 2= another even number so we want to find 3 consecutive even numbers that add up to 96 or
x is the first number
x+2 is the second number
x+4 is the third number
x+x+2+x+4=96
3x+6=96
subtract 6 from both sides
3x=90
divide both sides by 3
x=30
the first number is 30
x+2=32=second number
x+4=34=third number
the numbers are 30,32,34
Answer:
The least common multiple would be 140.
Step-by-step explanation:
The least common multiple is known to be a multiple that is the lowest value that satisfies being a multiple with the other factors given.
The least common multiple was 140 as it was the lowest value that satisfied being a multiple of 14, 10, AND, 20,
14 * 10 = 140
20 * 7 = 140
10 * 14 = 140
Answer:
270
Step-by-step explanation:
I am not sure if i am correct but i think you should divide 6,480 by 24 which is 270
