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Vlada [557]
2 years ago
7

This one i need help with tooo

Mathematics
1 answer:
BabaBlast [244]2 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

1 loaf requires 565 g of flour , then

p loaves requires 565p g of flour

100 g is required for sprinkling , then

total amount of flour = 565p + 100

Equate expression to 3700 and solve for p

565p + 100 = 3700 ( subtract 100 from both sides )

565p = 3600 ( divide both sides by 565 )

p = 6.37168.....

Thus a maximum of 6 loaves can be made

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Joe earns $14 an hour and Blaine earns $18 per hour. Joe receives a raise of $1.75 every six months, and Blaine receives a raise
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After 4 interval of six months, Joe to earn same hourly rate as Blaine

<em><u>Solution:</u></em>

Given that,

Amount earned by Joe = $ 14 per hour

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Therefore,

Joe earning: 14 + 1.75(number of six month intervals)

Equation for Joe earning: 14 + 1.75x ------- eqn 1

<em><u>Blaine receives a raise of $0.75 every six months</u></em>

Therefore,

Blaine earning: 18 + 0.75(number of six month intervals)

Equation for Blaine earning: 18 + 0.75x ------------ eqn 2

The number of six-month intervals it will take Joe to earn the same hourly rate as Blaine,

Eqn 1 must be equal to eqn 2

14+1.75x = 18+0.75x\\\\1.75x-0.75x = 18-14\\\\1x = 4\\\\x = 4

Thus after 4 interval of six months, Joe to earn same hourly rate as Blaine.

8 0
3 years ago
What does this image show? A) How to add. B) Information about exponential notation. C) Bow to multiply and divide. Will Mark Br
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