Answer:
I don't know I don't know I don't know
Answer:
Thus we find that velocity vector at time t is
(5t+15, 5t^2/2, 4t^2)
Step-by-step explanation:
given that acceleration vector is a funciton of time and at time t

v(t) can be obtained by integrating a(t)
v(t) = 
Thus we use the fact that acceleration is derivative of velocity and velocity is antiderivative of acceleration.
The arbitary constant normally used for integration C is here C vector = initial velocity (u0,v0,w0)
Position vector can be obtained by integrating v(t)
Thus we find that velocity vector at time t is
(5t+15, 5t^2/2, 4t^2)
Answer:
77 degrees and 90 degrees
The angle d is shown as 90 by the perfect right angle. The angle e has to equal 180 when added to f. So 180-103=77.
Using the Sine rule,

![\begin{gathered} \text{Let A = 14m,} \\ Substituting the variables into the formula,Where the length of the wires are, AP = xm and BP = ym[tex]\begin{gathered} \frac{\sin80^0}{14}=\frac{\sin40^0}{x} \\ \text{Crossmultiply,} \\ x\times\sin 80^0=14\times\sin 40^0 \\ Divide\text{ both sides by }\sin 80^0 \\ x=\frac{14\sin40^0}{\sin80^0} \\ x=9.14m \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7BLet%20A%20%3D%2014m%2C%7D%20%5C%5C%20Substituting%20the%20variables%20into%20the%20formula%2C%3Cp%3EWhere%20the%20length%20of%20the%20wires%20are%2C%20AP%20%3D%20xm%20and%20BP%20%3D%20ym%3C%2Fp%3E%5Btex%5D%5Cbegin%7Bgathered%7D%20%5Cfrac%7B%5Csin80%5E0%7D%7B14%7D%3D%5Cfrac%7B%5Csin40%5E0%7D%7Bx%7D%20%5C%5C%20%5Ctext%7BCrossmultiply%2C%7D%20%5C%5C%20x%5Ctimes%5Csin%2080%5E0%3D14%5Ctimes%5Csin%2040%5E0%20%5C%5C%20Divide%5Ctext%7B%20both%20sides%20by%20%7D%5Csin%2080%5E0%20%5C%5C%20x%3D%5Cfrac%7B14%5Csin40%5E0%7D%7B%5Csin80%5E0%7D%20%5C%5C%20x%3D9.14m%20%5Cend%7Bgathered%7D)
Hence, the length of wire AP (x) is 9.14m.
For wire BP (y)m,
Sum of angles in a triangle is 180 degrees,


Using the side rule to find the length of wire BP,

Hence, the length of wire BP (y) is 12.31m
Therefore, the length of the wires are (9.14m and 12.31m).