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coldgirl [10]
3 years ago
9

A hockey team is revealing their championship banner outside their stadium. The banner is in the shape of a triangle with a heig

ht that is 4 times as tall as the base length of the banner. If the total area of the banner is 18 square meters (18m2), what is the length of the base of the banner in meters?
Mathematics
1 answer:
kipiarov [429]3 years ago
5 0

Answer: the length of the base of the banner is 3 meters.

Step-by-step explanation:

Assuming the banner is in the shape of a right angle triangle, we would apply the formula for determining the area of a triangle which is expressed as

Area = 1/2 × base × height

Let b represent the base

The banner is in the shape of a triangle with a height that is 4 times as tall as the base length of the banner. It means that the height of the banner is 4b

If the total area of the banner is 18 square meters, it means that

18 = 1/2 × b × 4b

18 = 2b²

b² = 18/2 = 9

b = √9 = 3 meters

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For this case we have that the surface area of the prism is given by:

SA = A_ {l} + 2B

Where:

A_{l}: Is the lateral area

B: It is the area of the base

A_ {l} = P.h

Where:

Q: It is the perimeter of the base

h: It's the height

A_ {l} = 40 * 4\\A_ {l} = 160 \ in ^ 2

On the other hand:

B = 12 * 8\\B = 96 \ in ^ 2

So, we have:

SA = A_ {l} + 2B\\SA = 160 \ in ^ 2 + 2 * 96 \ in ^ 2\\SA = 352 \ in ^ 2

Answer:

SA = 352 \ in ^ 2

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I hope that helps you out!!

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