Answer:
If Raven's monthly payment were $125, the amount of the loan that she is considering taking out would be less than $43,205.56.
Step-by-step explanation:
If you think about it this way it may be more simple. If the APR stays constant then a greater payment will result in a greater loan. The opposite is also true meaning a lesser payment will result in a lesser loan. If the amount Raven pays is greater than $145 then the loan will be greater than $43,205.56. If the amount she pays is less than $145 then the loan will be less than $43,205.56. Of the options, only one of these situations will be present. In my case, the correct option was a payment of $125 will result in a lesser loan than $43,205.56.
Easy,
finding the complement (net price) subtract the discount percentage by 100% to get the net price percentage. Net price equals the list price minus the discount price.
100%-35%=65%
Multiply the list price ($1,400) by the complement.
Net price= 0.65(1,400)=$910
Thus, the new price is, $910.
This is how i worked it out.
Good Luck
Step-by-step explanation:
x = number hours dog walking
y = number hours tutoring
x + y <= 11
6x + 10y >= 80
the solution is the common area below the first line and above the second line.
the first line is above the second line (due to the y-intercept of 11 vs. 8) until the crossing point.
for the crossing point we use the regular equations :
from the first we get
x = 11 - y
using this in the second
6×(11 - y) + 10y = 80
66 - 6y + 10y = 80
4y = 14
y = 14/4 = 7/2 = 3.5
x = 11 - y = 11 - 3.5 = 7.5
so, she has to do at least 3.5 hours tutoring (and then 7.5 hours dog walking) for the minimum of $80 earning, all the way up to the maximum of 11 hours tutoring (and 0 dog walking) for $110 earning.
The volume of a sphere is given by the equation
, where r is the radius.
We are given the diameter of the sphere, but recall that the diameter is twice the radius:
. So the radius is half of the diameter:
.
Half of 8 cm is 4 cm.
We substitute this for r in the equation and we use 3.14 for <span>π.</span>
