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irakobra [83]
3 years ago
15

What is the formula used to find the circumference of a circle?

Mathematics
2 answers:
nirvana33 [79]3 years ago
6 0

Answer:

The circumference of a circle is c=3.14r

Step-by-step explanation:

kkurt [141]3 years ago
6 0

The circumference off the circle is

C = 3.14r

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What is the discriminant of 3x2 + 6x = 2?. a.12. b.18. c.42. d.60
Vikki [24]
<u><em>Answer:</em></u>
D. 60

<u><em>Explanation:</em></u>
<u>The general form of the quadratic equation is:</u>
ax² + bx + c = 0

<u>The given equation is:</u>
3x² + 6x = 2
This can be rewritten as:
3x² + 6x - 2 = 0

<u>By comparison, we can find that:</u>
a = 3
b = 6
c = -2

<u>Now, the discriminant of a quadratic equation is given by:</u>
b² - 4ac

<u>Substitute with the given values to get the discriminant for the given equation as follows:</u>
b² - 4ac = (6)² - 4(3)(-2) 
             = 36 - (-24)
             = 36 + 24
             = 60

Hope this helps :)
4 0
3 years ago
Read 2 more answers
Form an identity using -5x+9=9_
koban [17]

Answer:

-5x+9=9

-5x+9-9=9-9

-5x=0

   x= 0/5

   x= 0

Step-by-step explanation:

7 0
4 years ago
The average ticket price for a concert at the opera house was $50. The average attendance was 4000. When the ticket price was ra
kotegsom [21]

Answer

given,

opera house ticket = $50

attendance = 4000 persons

now,

opera house ticket = $52

attendance = 3800 person

assuming these are the points on the demand curve

(x, p) = (4000,50) and (x,p) = (3800,52)

using point slope formula

p-50 = \dfrac{50-52}{4000-3800}(x - 4000)

p-50 = \dfrac{-2}{200}(x - 4000)

p-50 = \dfrac{-x}{100}+ 40

p = \dfrac{-x}{100}+ 90

R(x) = x . p

R(x) = x (\dfrac{-x}{100}+ 90)

R(x) = \dfrac{-x^2}{100}+ 90x)

\dfrac{d}{dx}(R(x)) = \dfrac{d}{dx}(\dfrac{-x^2}{100}+ 90x))

\dfrac{d}{dx}(R(x)) = (\dfrac{-2x}{100})+90)

at \dfrac{d}{dx}(R(x)) = 0

\dfrac{-2x}{100}= -90

x = 4500

\dfrac{d^2}{d^2x}(R(x)) = -ve

hence at x =4500 the revenue is maximum

for maximum revenue ticket price will be

p = \dfrac{-4500}{100}+ 90

p = $45

6 0
3 years ago
This is #16. Now #17 says “For question #16, find a value of x that makes lines u and v intersect.” Help me.
pashok25 [27]
When you solved for x in #16, you were looking for the value of x to see what x would make both angles congruent since they were alternate interior angles. The same solution x=8, is the solution to #17 when the two lines will intersect.
If you graph both lines they will intersect at x=8.
6 0
3 years ago
4x^2 + kxy - 9y^2 <br> How to solve for k?
Len [333]
-kxy=4x^2-9y^2
-kx=(4x^2/y)-9y
-k=4x/y-9y
k=-4x/y+9y
3 0
3 years ago
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